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The analog signal m(t) is given below m(t) = 4 cos 100 pt + 8 sin 200 pt + cos 300 pt, the Nyquist sampling rate will be | |
A. | 1/100 [Wrong Answer] |
B. | 1/200 [Wrong Answer] |
C. | 1/300 [Correct Answer] |
D. | 1/600 [Wrong Answer] |