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Two ammeters A and B both 0-10 A have internal resistance of 1 Ω and 0.5 Ω respectively. They are connected in parallel. If total current is 15 A, then | |
A. | I_{A} = I_{B} = 7.5 A [Wrong Answer] |
B. | I_{A} = 5 A, I_{B} = 10 A [Correct Answer] |
C. | I_{A} = 10 A, I_{B} = 5 A [Wrong Answer] |
D. | I_{A} = 9 A, I_{B} = 6 A [Wrong Answer] |
View Answer
Explanation:-
Answer : B Discuss it below : !! OOPS Login [Click here] is required to post your answer/result |
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- n_{0}ω_{0} + β for any arbitrary real β
- n_{0}ω_{0} + 2pk for any arbitrary integer k
n_{0}ω_{0} + 2pk for any arbitrary integer k
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1200 revolutions
1800 revolutions
2100 revolutions
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has a period 2p, decays with increasing x and has zeros at np, n = ± 1, ± 2
has a period p
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can be used
cannot be used
may be used, but it has no use
can't be determine to use
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0.5 x 10^{-15}
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Q_{N+1} = J + KQ_{N}
Q_{N+1} = KQ_{N} + JQ_{N}
Q_{N+1} = K + JQ_{N}