Question is ⇒ Consider the following; for a loss-less transmission line we can write, <ol style="list-style-type: decimal; padding-bottom:10px;"><li style="padding-top:10px;">Zin = - jz0 for a shorted line with l = λ/8</li><li style="padding-top:10px;">Zin = ± j ∞ for a shorted line with l = λ/4</li><li style="padding-top:10px;">Zin= jz0 for an open line with l = λ/2</li><li style="padding-top:10px;">Zin = 0 for a matched line of any length</li></ol> Select the correct answer using the codes given below codes., Options are ⇒ (A) 1, 2, (B) 2, 3, (C) 1, 3, (D) 2, 4, (E) , Leave your comments or Download question paper.

Question is ⇒ Consider the following; for a loss-less transmission line we can write, <ol style="list-style-type: decimal; padding-bottom:10px;"><li style="padding-top:10px;">Zin = - jz0 for a shorted line with l = λ/8</li><li style="padding-top:10px;">Zin = ± j ∞ for a shorted line with l = λ/4</li><li style="padding-top:10px;">Zin= jz0 for an open line with l = λ/2</li><li style="padding-top:10px;">Zin = 0 for a matched line of any length</li></ol> Select the correct answer using the codes given below codes., Options are ⇒ (A) 1, 2, (B) 2, 3, (C) 1, 3, (D) 2, 4, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	Consider the following; for a loss-less transmission line we can write, Z_in = - jz₀ for a shorted line with l = λ/8 Z_in = ± j ∞ for a shorted line with l = λ/4 Z_in= jz₀ for an open line with l = λ/2 Z_in = 0 for a matched line of any length Select the correct answer using the codes given below codes.
A.	1, 2 [Wrong Answer]
B.	2, 3 [Wrong Answer]
C.	1, 3 [Wrong Answer]
D.	2, 4 [Correct Answer]
View Answer 1 -1 Explanation:- Answer : D Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

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