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Q1. | A number given in binary as 0101.01 is to be scaled up 4 times. The scaled up binary is |

A. | 10101 [Correct Answer] |

B. | 1.0101 [Wrong Answer] |

C. | 404.04 [Wrong Answer] |

D. | 10.101 [Wrong Answer] |

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Explanation:-
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**Also Read Similar Questions Below :**

⇒ The PCM signal shown below uses amplitude level of +1 volt and -1 volt to represent binary symbol 0 and 1 respectively. Each code word consists of 4 bits. The sampled version of analog signal from which this PCM signal is derived

EB596

CD231

DA495

25B6A

⇒ In the graphical analysis of an amplifier circuit, the slope of dc load line depends on

load resistance only

collector supply voltage only

both load resistance and collector supply voltage

none of the above

⇒ The maximum concentration of the element which can be dissolved in solid silicon at a given temperature is termed as

Solid solubility

Dissolution coefficient

Solidification index

Concentration index

⇒ A universal shift register can shift

from left to right

from right to left

both from left to right and right to left

none of the above

⇒ Consider a control system shown in given figure. For slight variation in G, the ratio of open loop sensitivity to closed loop sensitivity will be give

1 : (1 + GH)

1 : (1 + GH)

^{- 1}

1 : (1 - GH)

1 : (1 - GH)

^{- 1}

⇒ The Hilbert transform of cos ω

_{1}

*t*+ sin ω

_{2}

*t*is

sin ω

_{1}

*t*+ cos ω

_{2}

*t*

sin ω

_{1}

*t*- cos ω

_{2}

*t*

cos ω

_{1}

*t*- cos ω

_{2}

*t*

sin ω

_{1}

*t*+ sin ω

_{2}

*t*

⇒ Two identical NMOS transistors M

_{1}and M

_{2}are connected as shown below. V

_{bias}is chosen so that both transistors are in saturation. The equivalent

*g*of the pair is defined t

_{m}the sum of individual

*g*'s of the transistors

_{m}the product of individual

*g*'s of the transistors

_{m}nearly equal to the

*g*of M

_{m}_{1}

nearly equal to

*g*/

_{m}*g*

_{0}of M

_{2}

⇒ A function table is required in very large numbers the memory most switched for this purpose would be

ROM

PROM

EPROM

EAROM

⇒ An

*E*transformer is a

displacement transducer

velocity transducer

acceleration transducer

pressure transducer

⇒ For the circuit of figure the input and output Miller resistances

5 kΩ each

1 ohm and 5 kΩ respectively

5 kΩ and 1 ohm respectively

1 ohm each

⇒ The resonance frequency is

ω

_{r}=

*a*

ω

_{r}=

*b*

ω

_{r}=

*k*

ω

_{r}=

*ba*

⇒ The maximum number of AM broadcast stations that can be accommodated in a 100 kHz bandwidth for the highest modulating frequency of 5 kHz will be

100

20

10

1

⇒ The conductivity of intrinsic semiconductor is given by

*en*

_{i}(μ

_{p}- μ

_{n})

*en*

_{i}(μ

_{p}+ μ

_{n})

*n*

_{i}(μ

_{p}+ μ

_{n})

*n*

_{i}(μ

_{p}μ

_{n})

⇒ 1's complement of 11100110 is

11001

10000001

11010

0

⇒ At a temperature of 7 K, lead is a superconductor.

TRUE

FALSE

⇒ In intrinsic semiconductor, the fermi level

lies at the centre of forbidden energy gap

is near the conduction band

is near the valence band

may be anywhere in the forbidden energy gap

⇒ A full wave bridge diode rectifier uses diodes having forward resistance of 50 ohms each. The load resistance is also 50 ohms. The voltage regulations is

0.2

0.5

1

2

⇒ In a CE amplifier circuit the ac voltage between emitter and ground

is very high

may be high or low

is zero

depends on circuit configuration

⇒ The diameter and thickness of CD are

6 cm and 1.2 mm

6 cm and 0.6 mm

12 cm and 0.6 mm

12 cm and 1.2 mm

⇒ Two currents have the same peak value. Wave 1 is sinusoidal and wave 2 is rectangular. The ratio of their heating effects are

0.0423611111111111

1 : 2

0.0430555555555556

0.000711805555555555

⇒ In the above case the total power in the modulated wave double sideband, suppressed carrier AM will be

112 W

400 W

415 W

512 W

⇒ The applications of shift registers are

- Time delay
- Ring counter
- Serial to parallel data conversion
- Serial to serial data conversion

1, 2, 3

2, 3, 4

1, 2, 3, 4

1, 2, 4

⇒ For the BJT shown in figure, β = 50, the value of V

_{CE}

3.13 V

4.24 V

5.18 V

none

⇒ The Table given below is the mark obtained by 2 students in 8 different subjec

-0.4748

0.4748

-0.0338

0.0338

⇒ One eV = 1.602 x 10

^{-19}joules.

TRUE

FALSE

⇒ In a second order system ω

*= 10 rad/sec and ζ = 0.1, then ω*

_{n}_{d}=

9.1 rad/sec

9.95 rad/sec

9 rad/sec

1 rad/sec

⇒ A

*Q*meter uses the principle of

variation of self inductance

variation of mutual inductance

series resonance

none of the above

⇒ The following statements are true with respect to "Cascode Amplifier".

- The reduction in
*h*_{12}and Miller capacitance result in negligible reverse internal feedback. - A's is large loads cannot be connected.
- As a narrow band amplifier, it provides small range of
*c*_{μ}is reduced. - As a narrow band amplifier it provides small range of frequencies parameters the effect of
*c*_{μ}reduces.

only 1

only 1 and 4

only 2 and 4

only 1 and 3

⇒ Which of the following statement regarding link loss for a satellite is wrong?

For fixed antenna, it is inversely proportional to

*f*

^{2}

For fixed frequency, it is inversely proportional to the product of the antenna aperture areas

For a given satellite operating at a given frequency, it is inversely proportional to

Loss in down-link is negligible as compared to that in uplink

⇒ Initially the number decimal 8 is stored. If instruction

`RAL`

is executed twice, the final number stored will bedecimals 8

decimal 16

decimal 32

decimal 2