Question is ⇒ Assertion (A): In a perfect capacitor, the current density is given by ω ∈0E0∈'rcos(ωt + 90°), where ∈r' is real part of dielectric constant.Reason (R): In a perfect capacitor, dielectric losses are zero., Options are ⇒ (A) Both A and R are true and R is correct explanation of A, (B) Both A and R are true but R is not correct explanation of A, (C) A is true but R is false, (D) A is false but R is true, (E) , Leave your comments or Download question paper.

Question is ⇒ Assertion (A): In a perfect capacitor, the current density is given by ω ∈0E0∈'rcos(ωt + 90°), where ∈r' is real part of dielectric constant.Reason (R): In a perfect capacitor, dielectric losses are zero., Options are ⇒ (A) Both A and R are true and R is correct explanation of A, (B) Both A and R are true but R is not correct explanation of A, (C) A is true but R is false, (D) A is false but R is true, (E) , Leave your comments or Download question paper. _rcos(ωt + 90°), where ∈_r^' is real part of dielectric constant.

Reason (R): In a perfect capacitor, dielectric losses are zero.

, Options are ⇒ (A) Both A and R are true and R is correct explanation of A, (B) Both A and R are true but R is not correct explanation of A, (C) A is true but R is false, (D) A is false but R is true, (E) , Leave your comments or Download question paper. '/> _rcos(ωt + 90°), where ∈_r^' is real part of dielectric constant.

Reason (R): In a perfect capacitor, dielectric losses are zero.


Q1.	Assertion (A): In a perfect capacitor, the current density is given by ω ∈₀E₀∈^'_rcos(ωt + 90°), where ∈_r^' is real part of dielectric constant. Reason (R): In a perfect capacitor, dielectric losses are zero.
A.	Both A and R are true and R is correct explanation of A [Correct Answer]
B.	Both A and R are true but R is not correct explanation of A [Wrong Answer]
C.	A is true but R is false [Wrong Answer]
D.	A is false but R is true [Wrong Answer]
View Answer 1 -1 Explanation:- Answer : A Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

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