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McMurray Bedford full bridge inverter uses | |
A. | natural commutation [Wrong Answer] |
B. | auxiliary commutation [Wrong Answer] |
C. | complementary commutation [Correct Answer] |
D. | any of the above [Wrong Answer] |
View Answer
Explanation:-
Answer : C Discuss it below : !! OOPS Login [Click here] is required to post your answer/result |
Also Read Similar Questions Below :
⇒ The function A e^{st} where s = s + jω represents
A phasor whose magnitude changes with time
A phasor whose frequency is ω
A phasor rotating in counterclockwise direction at angular frequency ω and whose magnitude increases with t
A phasor rotating in clockwise direction at angular frequency ω and whose magnitude increases with t
⇒ When the modulating frequency is doubled, the modulation index is halved and the modulating voltage remains constant. The modulation system is
FM
AM
phase modulation
none of the above
⇒ For BJT, under saturation condition
I_{C} = βI_{B}
I_{C} > bI_{B}
I_{C} is independent of all other parameters
I_{C} < βI_{B}
⇒ For the shaded area in Venn diagram of the given figure, the Boolean expressio
AB + BC + CA
ABC + A B C
ABC + A B C
ABC+AB
⇒ The total electrical energy emitted overall space from an electron of charge e and radius r is
e/ε_{0}r^{2}
e^{2}/ε_{0}r
e^{2}/4pε_{0}r^{2}
e^{2}/8pε_{0}r
⇒ If F(jω) is the Fourier transform of f(t), then
£ f(- t) = F(jω)
£ f(- t) = F* (jω)
£ f(- t) = F(- jω)
£ f(- t) = F* (- jω)
⇒ In a radio receiver, if the intermediate frequency is too high
Selectivity will be poor
Tracking difficulties will be least
Adjacent channel rejection will improve
All of the above will occur
⇒ Mark the false statement:
since wave-shape of a digital signal is unimportant, linear amplifiers are not required
the precise amplitude of a digital signal is also unimportant provided two voltage levels (0 and 1) are quite different
the leading and trailing edges of a digital signal need not be sharp
actual digital waves have rise and fall times of the order of a few nano seconds
⇒ If a microstrip is enclosed in a metal enclosure
the radiation losses are increased
the radiation losses are reduced RL
the capacitance becomes zero
the inductance becomes zero
⇒ In a piezoelectric crystal, application of a mechanical stress would produce
plastic deformation of the crystal
magnetic Dipoles in the crystal
electric polarization in the crystal
shift in the Fermi level
⇒ The reverse breakdown voltage of a diode depends on the extent of doping.
TRUE
FALSE
⇒ The purpose of incorporating a pre-selector stage in a receiver is to
provide higher selectivity
provide higher fidelity
improve linearity
larger passband
⇒ When a transistor is to be at a temperature above 25°C
smaller heat sink be provided
maximum power rating be derated
biasing circuit must be strengthened
earth connections must be connected through a resistor
⇒ For formation of state equations, the inductors and current sources
should be in tree
should be in cotree
may be in tree or cotree
should be in both tree and cotree
⇒ The frequency at which phase angle is 180° is called
phase crossover frequency
stability limit frequency
frequency of limited stability
gain margin frequency
⇒ Fourier analysis indicate that a square wave can be represented as
a fundamental sine wave and odd harmonics
a fundamental sine wave and even harmonics
a fundamental sine wave and harmonics
fundamental and subharmonic sine waves
⇒ The constellation diagram of a modem has four states as shown in the figure given below. What is the bit rate of this mod
Two times its band rate
Four times its band rate
Same as band rate
Sufficient information is not given to give the answer
⇒ Two 2's complement number having sign bits X and Y are added and the sign bit of the result is Z. then, the occurrence of overflow is indicated by the Boolean function.
XYZ
X Y Z
X YZ + XY Z
XY + YZ + ZX
⇒ In telephone, the dial tone has a frequency of
5 Hz
15 Hz
33 Hz
233 Hz
⇒ If Laplace transform of f(t) is F(s), then £ f(t - a) u (t - a)= 0
e^{as} F(s)
e^{-as} F(s)
- e^{as} F(s)
- e ^{-as} F(s)
⇒ The number of bits in ASCII is
12
10
9
7
⇒ ∈_{0} has no other physical meaning than that of a fundamental conversion factor.
TRUE
FALSE
⇒
A-1, B-3, C-4, D-2
A-2, B-1, C-3, D-4
A-1, B-2, C-3, D-4
A-4, B-2, C-1, D-3
⇒ If the midband gain of an amplifier is 40 dB, the gain at half power frequency is
37 dB
30 dB
20 dB
13 dB
⇒ Two sinusoidal signals of equal amplitude and frequency are applied to X and Y plate of CRO respectively. The observed Lissajous pattern is a straight line. The phase shift between signals is
zero
90°
either zero or 180°
either 90° or 270°
⇒ A padder is basically a/an
insulator
variable resistor
capacitor
inductor
⇒ In a 7 segment display, LEDs b and c lit up. The decimal number displayed is
9
7
3
1
⇒ A CE amplifier has r_{e} = 6 Ω, β = 100 and a = 0.98. The input impedance is
6 Ω
100 Ω
600 Ω
98 Ω
⇒ A liquid has N permanent dipoles μ_{p} per unit volume and has been subjected to dc field for a long time such that orientation polarization is P_{0}. At t = 0, the field is suddenly removed, then polarization
will remain constant at P_{0}
will become zero at t = 0
will delay to zero with a time constant
either b or c
⇒ A(A + B) =
A
A B
AB
AB
⇒ The function A e^{st} where s = s + jω represents
A phasor whose magnitude changes with time
A phasor whose frequency is ω
A phasor rotating in counterclockwise direction at angular frequency ω and whose magnitude increases with t
A phasor rotating in clockwise direction at angular frequency ω and whose magnitude increases with t
⇒ When the modulating frequency is doubled, the modulation index is halved and the modulating voltage remains constant. The modulation system is
FM
AM
phase modulation
none of the above
⇒ For BJT, under saturation condition
I_{C} = βI_{B}
I_{C} > bI_{B}
I_{C} is independent of all other parameters
I_{C} < βI_{B}
⇒ For the shaded area in Venn diagram of the given figure, the Boolean expressio
AB + BC + CA
ABC + A B C
ABC + A B C
ABC+AB
⇒ The total electrical energy emitted overall space from an electron of charge e and radius r is
e/ε_{0}r^{2}
e^{2}/ε_{0}r
e^{2}/4pε_{0}r^{2}
e^{2}/8pε_{0}r
⇒ If F(jω) is the Fourier transform of f(t), then
£ f(- t) = F(jω)
£ f(- t) = F* (jω)
£ f(- t) = F(- jω)
£ f(- t) = F* (- jω)
⇒ In a radio receiver, if the intermediate frequency is too high
Selectivity will be poor
Tracking difficulties will be least
Adjacent channel rejection will improve
All of the above will occur
⇒ Mark the false statement:
since wave-shape of a digital signal is unimportant, linear amplifiers are not required
the precise amplitude of a digital signal is also unimportant provided two voltage levels (0 and 1) are quite different
the leading and trailing edges of a digital signal need not be sharp
actual digital waves have rise and fall times of the order of a few nano seconds
⇒ If a microstrip is enclosed in a metal enclosure
the radiation losses are increased
the radiation losses are reduced RL
the capacitance becomes zero
the inductance becomes zero
⇒ In a piezoelectric crystal, application of a mechanical stress would produce
plastic deformation of the crystal
magnetic Dipoles in the crystal
electric polarization in the crystal
shift in the Fermi level
⇒ The reverse breakdown voltage of a diode depends on the extent of doping.
TRUE
FALSE
⇒ The purpose of incorporating a pre-selector stage in a receiver is to
provide higher selectivity
provide higher fidelity
improve linearity
larger passband
⇒ When a transistor is to be at a temperature above 25°C
smaller heat sink be provided
maximum power rating be derated
biasing circuit must be strengthened
earth connections must be connected through a resistor
⇒ For formation of state equations, the inductors and current sources
should be in tree
should be in cotree
may be in tree or cotree
should be in both tree and cotree
⇒ The frequency at which phase angle is 180° is called
phase crossover frequency
stability limit frequency
frequency of limited stability
gain margin frequency
⇒ Fourier analysis indicate that a square wave can be represented as
a fundamental sine wave and odd harmonics
a fundamental sine wave and even harmonics
a fundamental sine wave and harmonics
fundamental and subharmonic sine waves
⇒ The constellation diagram of a modem has four states as shown in the figure given below. What is the bit rate of this mod
Two times its band rate
Four times its band rate
Same as band rate
Sufficient information is not given to give the answer
⇒ Two 2's complement number having sign bits X and Y are added and the sign bit of the result is Z. then, the occurrence of overflow is indicated by the Boolean function.
XYZ
X Y Z
X YZ + XY Z
XY + YZ + ZX
⇒ In telephone, the dial tone has a frequency of
5 Hz
15 Hz
33 Hz
233 Hz
⇒ If Laplace transform of f(t) is F(s), then £ f(t - a) u (t - a)= 0
e^{as} F(s)
e^{-as} F(s)
- e^{as} F(s)
- e ^{-as} F(s)
⇒ The number of bits in ASCII is
12
10
9
7
⇒ ∈_{0} has no other physical meaning than that of a fundamental conversion factor.
TRUE
FALSE
⇒
Match the following:
List I | List II | ||
---|---|---|---|
A. | Sky wave | 1. | parasitic elements |
B. | Antenna feed | 2. | delta match |
C. | Reflector | 3. | long-wire antenna |
D. | Rhombic antenna | 4. | ionosphere |
A-1, B-3, C-4, D-2
A-2, B-1, C-3, D-4
A-1, B-2, C-3, D-4
A-4, B-2, C-1, D-3
⇒ If the midband gain of an amplifier is 40 dB, the gain at half power frequency is
37 dB
30 dB
20 dB
13 dB
⇒ Two sinusoidal signals of equal amplitude and frequency are applied to X and Y plate of CRO respectively. The observed Lissajous pattern is a straight line. The phase shift between signals is
zero
90°
either zero or 180°
either 90° or 270°
⇒ A padder is basically a/an
insulator
variable resistor
capacitor
inductor
⇒ In a 7 segment display, LEDs b and c lit up. The decimal number displayed is
9
7
3
1
⇒ A CE amplifier has r_{e} = 6 Ω, β = 100 and a = 0.98. The input impedance is
6 Ω
100 Ω
600 Ω
98 Ω
⇒ A liquid has N permanent dipoles μ_{p} per unit volume and has been subjected to dc field for a long time such that orientation polarization is P_{0}. At t = 0, the field is suddenly removed, then polarization
will remain constant at P_{0}
will become zero at t = 0
will delay to zero with a time constant
either b or c
⇒ A(A + B) =
A
A B
AB
AB