Question is ⇒ Which op-amp circuit uses a capacitor in series with input and resistance in feedback path?, Options are ⇒ (A) Differentiating amplifier, (B) Integrating amplifier, (C) Logarithmic amplifier, (D) None of the above, (E) , Leave your comments or Download question paper.

Question is ⇒ Which op-amp circuit uses a capacitor in series with input and resistance in feedback path?, Options are ⇒ (A) Differentiating amplifier, (B) Integrating amplifier, (C) Logarithmic amplifier, (D) None of the above, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	Which op-amp circuit uses a capacitor in series with input and resistance in feedback path?
A.	Differentiating amplifier [Correct Answer]
B.	Integrating amplifier [Wrong Answer]
C.	Logarithmic amplifier [Wrong Answer]
D.	None of the above [Wrong Answer]
View Answer 1 -2 Explanation:- Answer : A Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

Previous question Next question

Also Read Similar Questions Below :

⇒ For high frequencies a capacitor like
an open circuit
a short circuit
either open circuit or short circuit
none of the above

⇒ In a CE amplifier, the collector resistance is 6 kΩ and load resistance is 3 kΩ. The ac load resistance is
9 kΩ
6 kΩ
3 kΩ
2 kΩ

⇒ Consider the following program in C 1
-1
1.15
-1.15

⇒ Consider the following statements:

In the 2's complement representation, negative numbers are stored in sign magnitude form.
Taking 2's complement is equivalent to sign change.
In a 4 bit complement representation of a binary number A.
In the 2's complement representation the most significant bit (MSB) is zero for a positive number.

Of these, the only true statements are
(I) and (III)
(I) and (IV)
(II) and (III)
(II) and (IV)

⇒ The number of p-n junctions in a semiconductor diode are
0
1
2
1 or 2

⇒ An antenna has a resistance of 50 Ω and an equivalent noise resistance of 30 Ω The noise figure in decibels is
1.6 dB
2 dB
3.6 dB
6 dB

⇒ The gain of an FET amplifier can be changed by changing
r_m
g_m
R_d
none of the above

⇒ The minimum number of 2 input NAND gates required to implement Boolean function A B C is A, B, C are available is
2
3
5
6

⇒ Beamwidth (between first nulls) will be for an antenna at 3 MHz with directivity of 100
140°
70°
210°
60°

⇒ Which is the dominant mode in rectangular waveguides?
TE₁₀
TE₁₁
TE₀₁
TM₁₁

⇒ Voice signal band limited to 3.4 KHz is sampled and pulse code modulated using 64 quantization levels. Ten such signals are time division multiplexed using one 5-bit synchronizing word every alternate frame. The minimum channel bandwidth required for transmission of the TDM signal is
100 KHz
200 KHz
50 KHz
150 KHz

⇒ In order to rectify sinusoidal signals of millivolt range (< 0.6 V)
bridge rectifier using diodes can be employed
full wave diode rectifier can be used
a diode is to be inserted in the feedback loop of an op-amp
a diode is to be inserted in the I/P of an op-amp

⇒ Which of the following statements is/are true for the diamond structure?

Coordination number is four.
Packing fraction is 0.34
Copper crystallizes into diamond structure
Lattice is FCC.

1 only
1, 2 and 4
2 and 3 only
2, 3 and 4

⇒ Cassergain feed is used with a parabolic reflector to
increase the gain of the system
increase the beamwidth of the system
reduce the size of the main reflector
allow the feed to be placed at a convenient point

⇒

Assertion (A): The velocity factor of a line is the ratio of wave velocity on the line to speed of light.

Reason (R): If the conductors of a line are immersed in a non magnetic insulating liquid, the wave velocity increases.

Both A and R are correct and R is correct explanation of A
Both A and R are correct but R is not correct explanation of A
A is correct but R is wrong
A is wrong but R is correct

⇒ For the floating point numbers 1.81 x 10^-29 and 0.0152 x 10¹⁸ the normalised forms are
0.181 x 10^-28 and 0.152 x 10¹⁷respectively
18.1 x 10^-30 and 0.152 x 10¹⁷ respectively
0.181 x 10^-28 and 1.52 x 10¹⁶ respectively
None of the above

⇒ In an ac circuit the fundamental component of current wave lags the corresponding voltage wave by 20°. The third harmonic component of current wave lags the corresponding voltage by an angle.
less than 20°
more than 20°
equal to 20°
equal to or more than 20°

⇒ If VSWR is infinite, the transmission line is terminated in
short circuit
complex impedance
open circuit
either (a) or (c)

⇒ In a broadcast superheterodynes receiver having no RF amplifier, the loaded Q of the antenna coupling circuit is 100. If the intermediate frequency is 455 kHz. The image frequency at 25 MHz will be
24.09 MHz
24.54 MHz
25.45 MHz
25.91 MHz

⇒ The clock shown in figure has a frequency of 6 MHz. The frequency of the Q output wil
12 MHz
24 MHz
3 MHz
1.5 MHz

⇒ For the logic circuit given, what is the simplified Boolean funct
X = AB + C
X = BC + A
X = AB + AC
X = AC + B

⇒ Two transistors have same value of a but different gain (G) bandwidth (B) product. The transistors have similar geometry. However one of them is germanium and the other is silicon. The transistor with lower GB product
is germanium
is silicon
may be either of two
cannot be identified on the basis of above data

⇒ It is required to increase the maximum range of a radar by a factor of two. The peak power transmitted in the radar system has to be increased by a factor of
2
4
8
16

⇒ In a bridge inverter with single pulse width modulation
the output frequency is equal to frequency of reference signal
the output frequency is equal to frequency of control signal
either (a) or (b)
neither (a) nor (b)

⇒ A capacitor can be represented by a capacitance and resistance in parallel. For a good capacitor, this parallel resistance should be
negligible
low
high
very high

⇒ Which of the following is not true as regards communication receiver?
It is exactly same as radio receiver used in households
It can be used, besides communication, for detection in high frequency bridges
It is designed to perform the task of low and high frequency reception better than in household receiver
Its tuning and operation are more complicated than those in household receiver

⇒ Inverters find applications in
HVDC transmission
UPS
variable speed ac drives
all of the above

⇒ If the plate supply voltage for a plate modulated class C amplifier is E, the maximum plate cathode voltage could be almost as high as
E
2 E
3 E
4 E

⇒ In following circuit, R_B will be if V_CC = 10 V, V_S = 2 V, R_C = 5 kΩ, R_S = 90 kΩ, β = 50, I_CE = 0, V_CEsat = 0
230 K
235 K
240 K
250 K

⇒ The maximum permissible distance between two samples of a 2 kHz signal is
1000 μ sec
500 μ sec
250 μ sec
2000 sec