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Q1. | The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age will be twice that of his son. The ratio of their present ages is: |

A. | 5 : 2 [Wrong Answer] |

B. | 7 : 3 [Correct Answer] |

C. | 9 : 2 [Wrong Answer] |

D. | 13 : 4 [Wrong Answer] |

View Answer
Explanation:-
Answer : BDiscuss it below :Let the present age of father b ‘x’ years and son be ‘y’ years10 years ago, father age = x-10; son’s age = y – 10 Given : The age of father 10 years ago was thrice the age of son X – 10 = 3 (y-10) X – 10 = 3y – 30 ⇒ x – 3y = - 20 ---------------- (1) Given : Then 10 years after, father age is twice of his son X + 10 = 2 (y+10) X + 10 = 2y + 20 ⇒ x – 2y = 10 -----------------(2) (1) - (2) we get y = 30 and x = 70 To find : x : y 70 : 30 ⇒ 7 : 3 !! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

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