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Q1. | The present ages of three persons are in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years). |

A. | 8, 20, 28 [Wrong Answer] |

B. | 16, 28, 36 [Correct Answer] |

C. | 20, 35, 45 [Wrong Answer] |

D. | None of these [Wrong Answer] |

View Answer
Explanation:-
Answer : BDiscuss it below :Let the 3 persons be A, B and CGiven : The ratio of the present ages of 3 persons is 4:7:9 Let the present age of A be 4x years Let the present age of B be 7x years Let the present age of C be 9x years A : B : C ⇒ 4x : 7x : 9x Given : 8 years ago, the sum of their ages was 56. 8 years ago, the ratio of the ages is A : B : C ⇒ 4x – 8 : 7x – 8 : 9x – 8 Given : The sum of the above ages was 56 4x -8 + 7x-8 + 9x-8 = 56 20x – 24 = 56 ⇒ 20x = 56+24 Download More Aptitude Questions,Reasoning questions,Puzzles ⇒ 20x=80 x = 4 To find : A, B and C’s present age. A : B : C 4x : 7x : 9x ∴ ⇒ 4 (4) : 7 (4) : 9 (4) A’s Age = 16 ; B’s Age = 28 ; C’s Age = 36 !! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

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