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Q1. | The present ages of three persons are in proportions 4:7:9.Eight years ago, the sum of their ages was 56. Find their present ages (in years). |

A. | 8,20,28 [Wrong Answer] |

B. | 16,28,36 [Correct Answer] |

C. | 20,35,45 [Wrong Answer] |

D. | None of these [Wrong Answer] |

View Answer
Explanation:-
Answer : BDiscuss it below :let their present ages be 4x,7x and 9x years respectively.then, (4x-8)+(7x-8)+(9x-8)=56 => 20x=80 => x=4 therefore their present ages are 16 years, 28 years, 36 years respectively !! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

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