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Tickets numbered 1 to 100 are placed in a box. Find the probability that a ticket selected at random has a number that is divisible by both 3 and 5. | |
A. | 3/20 [Wrong Answer] |
B. | 3/50 [Correct Answer] |
C. | 1/15 [Wrong Answer] |
D. | 3/25 [Wrong Answer] |