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Q1. | While using three moments equation, a fixed end of a continuous beam is replaced by an additional span of |

A. | zero length [Correct Answer] |

B. | infinite length [Wrong Answer] |

C. | zero moment of inertia [Wrong Answer] |

D. | none of the above [Wrong Answer] |

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Explanation:-
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**Also Read Similar Questions Below :**

⇒ The analysis of statically indeterminate structures by the unit load method is based on

Consistent deformation

Stiffness method

Consistent force

None of these

⇒ The torsional stiffness of a member can be defined as

Torque for unit moment

Torque for unit twist

Moment for unit twist

Torsion for unit twist

⇒ The horizontal thrust due to rise in temperature in a semicircular two-hinged arch of radius R is proportional to

R

R

^{2}

1/R

1/R

^{2}

⇒ Degree of static indeterminacy of a rigid-jointed plane frame having 15 members, 3 reaction components and 14 joints is

2

3

6

8

⇒ For a single point load W moving on a symmetrical three hinged parabolic arch of span L, the maximum sagging moment occurs at a distance x from ends. The value of x is

0.211 L

0.25 L

0.234 L

0.5 L

⇒ A load 'W is moving from left to right support on a simply supported beam of span T. The maximum bending moment at 0.4 1 from the left support is

0.16 Wl

0.20 Wl

0.24 Wl

0.25 Wl

⇒ The method of virtual work in the analysis of structures results is

Compatible deformations

Equilibrium of forces

Stress strain relations

None of these

⇒ Minimum compressive strength in N/mm2 for H1 type mortar used for masonry is

3

5

7.5

10

⇒ Select the correct statement

Flexibility matrix is a square symmetrical matrix

Stiffness matrix is a square symmetrical matrix

both (a) and (b)

none of the above

⇒ Degree of kinematic indeterminacy of a pin-jointed plane frame is given by

2j - r

j - 2r

3j - r

2j + r

⇒ Weaker mortar. Of these statements

2 and 3 are correct

1 and 2 are correct

1 and 3 are correct

1, 2 and 3 are correct

⇒ For a symmetrical two hinged parabolic arch, if one of the supports settles horizontally, then the horizontal thrust

is increased

is decreased

remains unchanged

becomes zero

⇒ For earthquake resistant masonry buildings, where seismic coefficient is less than 0.08, the horizontal distance between two openings shall not be less than

Vt x height of shorter opening

Vt x height of longer opening

Ax height of shorter opening

Vi x height of longer opening

⇒ To generate the j th column of the flexibility matrix

a unit force is applied at coordinate j and the displacements are calculated at all coordinates

a unit displacement is applied at co-ordinate j and the forces are calculated at all coordinates

a unit force is applied at coordinate j and the forces are calculated at all coordinates

a unit displacement is applied at co-ordinate j and the displacements are calculated at all co-ordinates

⇒ Direct load carrying capacity of a brick masonry wall standing freely as against when it supports RC slab will be

more

less

the same in both the cases

100%

⇒ The mode of failure of a very short masonry member having h/t ratio of less than 4 is by

shear

vertical tensile splitting

buckling

any of the above

⇒ When a load crosses a through type Pratt truss in the direction left to right, the nature of force in any diagonal member in the left half of the span would

change from compression to tension

change from tension to compression

always be compression

always be tension

⇒ The width of the analogous column in the method of column analogy is

2/EI

1/EI

1/2 EI

1/4 EI

⇒ When a uniformly distributed load, longer than the span of the girder, moves from left to right, then the maximum bending moment at mid section of span occurs when the uniformly distributed load occupies

less than the left half span

whole of left half span

more than the left half span

whole span

⇒ The method of moment distribution in structural analysis is

An iterative method

An exact method

An approximate method

None of these

⇒ Principle of superposition is applicable when

deflections are linear functions of applied forces

material obeys Hooke's law

the action of applied forces will be affected by small deformations of the structure

none of the above

⇒ The stiffness method in structural analysis is also known as

Unit load method

Consistent deformation method

Force method

Displacement method

⇒ In moment distribution method, the sum of distribution factors of all the members meeting at any joint is always

zero

less than 1

1

greater than 1

⇒ In column analogy method, the area of an analogous column for a fixed beam of span L and flexural rigidity El is taken as

L/EI

L/2EI

L/3EI

L/4EI

⇒ When a uniformly distributed load, shorter than the span of the girder, moves from left to right, then the conditions for maximum bending moment at a section is that

the head of the load reaches the section

the tail of the load reaches the section

the load position should be such that the section divides it equally on both sides

the load position should be such that the section divides the load in the same ratio as it divides the span

⇒ The Castigliano's second theorem can be used to compute deflections

in statically determinate structures only

for any type of structure

at the point under the load only

for beams and frames only

⇒ If in a rigid-jointed space frame, (6m + r) < 6j, then the frame is

unstable

stable and statically determinate

stable and statically indeterminate

none of the above

⇒ The fixed support in real beam becomes in the conjugate beam is

Fixed support

Hinged support

Roller support

Free support

⇒ For a two-hinged arch, if one of the supports settles down vertically, then the horizontal thrust

is increased

is decreased

remains unchanged

becomes zero

⇒ A free standing brick wall 20 cm thick is subjected to a wind pressure of 75kg/m2. The maximum height of wall from stability consideration is

0.64 m

0.96 m

1.28 m

1.5 m