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Q1. | Which of the following is used as switch? |

A. | J-K flip-flop [Wrong Answer] |

B. | Master slave J-K flip-flop [Wrong Answer] |

C. | T-flip-flop [Wrong Answer] |

D. | D-flip-flop [Correct Answer] |

View Answer
Explanation:-
Answer : DDiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ When a current flows through a coil of insulated wire, the coil shows the properties of a magnet.

TRUE

FALSE

⇒

**Assertion (A):** Power loss in a conductor of resistance P = I^{2}R.

**Reason (R):** When a conductor is carrying current with current density J as a result of applied field E, then heat developed/m^{3}/ second = JE.

Both A and R are true and R is correct explanation of A

Both A and R are true but R is not correct explanation of A

A is true but R is false

A is false but R is true

⇒ The following statements are true with respect to "Cascode Amplifier".

- The reduction in
*h*_{12}and Miller capacitance result in negligible reverse internal feedback. - A's is large loads cannot be connected.
- As a narrow band amplifier, it provides small range of
*c*_{μ}is reduced. - As a narrow band amplifier it provides small range of frequencies parameters the effect of
*c*_{μ}reduces.

only 1

only 1 and 4

only 2 and 4

only 1 and 3

⇒ Thermistor has a positive temperature coefficient.

TRUE

FALSE

⇒ 1274

_{16}- 3A7

_{16}= __________ .

ACA

_{16}

ACB

_{16}

ECD

_{16}

AAA

_{16}

⇒ For air filled circular waveguides

the attenuation due to imperfect conducting walls is negligible

the attenuation due to imperfect dielectric is negligible

both the attenuation i.e. due to imperfect conducting walls and due to imperfect dielectric are significant

the total attenuation is almost zero

⇒ A chopper cannot be line commutated.

TRUE

FALSE

⇒ In a positive edge triggered JK flip flop

High J and High K produce inactive state

Low J and High K produce inactive state

Low J and Low K produce inactive state

High J and Low K produce inactive state

⇒ A linear time-invariant, causal continuous time system has a rational transfer function with simple poles at

*s*= - 2 and

*s*= - 4, and one simple zero at

*s*= - 1. A unit step

*u*(

*t*) is applied at the input of the system. At steady state, the output has constant value of 1. The impulse response of this system is

[exp (- 2

*t*) + exp (-4

*t*)]

*u*(

*t*)

[-4 exp (- 2

*t*) + 12 exp (-4

*t*) - exp (-

*t*)]

*u*(

*t*)

[-4 exp (- 2

*t*) + 12 exp (-4

*t*)]

*u*(

*t*)

[-0.5 exp (- 2

*t*) + 1.5 exp (-4

*t*)]

*u*(

*t*)

⇒ If CS = A

_{15}A

_{14}A

_{13}is used as chip select logic of a 4 K RAM in 8085 system, its memory range is

3000 H - 3 FFF H

7000 H - 7 FFFH

5000 H - 5 FFF H and 6000 H - 6 FFF H

6000 H - 6 FFF H and 7000 H - 7 FFF H

⇒ In a CMOS CS amplifier, the active load is obtained by connecting a

p channel current mirror circuit

n channel transistor

p channel transistor

BJT current mirror

⇒ In an ideal diode there is no breakdown, no __________ current, and no forward __________ drop.

reverse, voltage

forward, current

forward, voltage

reverse, current

⇒ The static equalisation circuit for thyristors connected in series is

one resistor in series with each thyristor

one resistor in parallel with each thyristor

one resistor and one capacitor in parallel with each thyristor

none of the above

⇒ A hollow rectangular waveguide has dimensions

*a*= 2

*b*. Calculate the amount of attenuation, if the frequency is 3 GHz, and

*b*= 1 cm.

49

47.33

50.33

50

⇒ Which of the following devices has a silicon dioxide layer?

NPN transistor

Tunnel diode

JFET

MOSFET

⇒ The figure of merit for a logic family is

gain band width product

(propagation delay time) (power dissipation)

(fan out) (power dissipation)

(noise margin) (power dissipation)

⇒ The circuit in figur

positive clamper

negative clamper

positive peak clipper

negative peak clipper

⇒

Match the following:

List I | List II | ||
---|---|---|---|

A. | Darlington amplifier | 1. | A circuit using pnp and npn transistors |

B. | CB amplifier | 2. | A CS amplifier driving a CG amplifier |

C. | Cascade amplifier | 3. | A circuit with over-all voltage gain close to 1 and very large input impedance |

D. | Complementary symmetry amplifier | 4. | A circuit with low input impedance |

A-1, B-2, C-3, D-4

A-2, B-1, C-3, D-4

A-3, B-4, C-2, D-1

A-4, B-3, C-2, D-1

⇒ In the output of a DM speech encoder, the consecutive pulses are of opposite polarity during time interval

*t*

_{1}<

*t*<

*t*

_{2}. This indicates that during this interval

the input to the modulator is essentially constant

the modulator is going through slope overload

the accumulator is in saturation

the speech signal is being sampled at the Nyquist rate

⇒ A dc network has an open circuit voltage of 5 V. When its terminals are short circuited a current of 5 A flows through the short circuit. If the short circuit is removed and a resistance of 1.5 Ω is connected across its terminals, the current will be

0.0416666666666667

0.0833333333333333

2.5 A

0.208333333333333

⇒ Microprocessors were introduced in the year

1951

1961

1971

1981

⇒ The direction of rotation of a CD is

clockwise

anticlockwise

clockwise or anticlockwise depending on frequency of data stored

mostly anticlockwise but some times clockwise

⇒ For a n-channel JFET with

*r*

_{0}= 10 kW, (V

_{Gs}= 0 V, V

_{P}= - 6 V)the drain resistance

*r*

_{d}at V

_{GS}= - 3 V is given by

40 kΩ

2.5 kΩ

4.44 kW

120 kW

⇒ A ripple in collector supply voltage of the output stage of amplifier causes noise.

TRUE

FALSE

⇒ In a oscillator, a sine wave generator starts at

*t*= 0. It consist of

Pure sine wave

Pure cosine wave

Unity for

*t*> 0

2∪(

*t*) - 1

⇒ With a variable reluctance tachometer having 60 rotor teeth the count reads 3600 counts per minute. The speed in RPM is

36

60

360

3600

⇒ A plane EM wave is travelling in an unbound loss less dielectric having μ

_{y}= 1 and ε

_{y}= 4, the time average Poynting vector of the wave is 5 W/m

^{3}. The phase velocity

*v*

_{p}(assuming velocity of light as 3 x 10

^{8}m/sec) is

1.5 x 10

^{8}m/sec

3 x 10

^{8}m/sec

2.5 x 10

^{8}m/sec

0.5 x 10

^{8}m/sec

⇒ A XOR gate has inputs A and B and output Y. Then the output equation is

Y = AB

Y = AB + A B

Y = A B + A B

Y = A B + A B

⇒ Twelve resistance each 2 ohm are connected to form a cube, one resistance being in each arm of cube. The resistance between any two diagonally opposite comers is

1 Ω

2 Ω

4 Ω

8 Ω

⇒ The modulation index of an AM wave is changed from 0 to 1. The transmitted power is

unchanged

halved

increased by 50%

quadrupled