Users Also Read

MCQ's Search Engine

Electrical Engineering

Mechanical Engineering

Civil Engineering

Automobile Engineering

Chemical Engineering

Computer Engineering

Electronics Engineering

Medical Science Engg

Q1. | Which component is allowed to pass through it by a choke filter? |

A. | Dc [Correct Answer] |

B. | Ac [Wrong Answer] |

C. | Both dc and ac [Wrong Answer] |

D. | Only high frequency ac [Wrong Answer] |

View Answer
Explanation:-
Answer : ADiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ The Boolean expression for the shaded area in the Venn diagra

X + Y + Z

XY + Z + X YZ

X Y Z + XY

X + Y + Z

⇒ Nodal analysis is applicable to __________ .

planar network

planar and Non-planar both

circuit containing only voltage source

non planer

⇒ An engineer designs an amplifier to have a voltage gain of 60, but when constructed it only had a gain of 50. Which of the following will increases from this type of operation?

Stability

Bandwidth

Distortion

Input resistance

⇒ Two similar mutually coupled coils have a total inductance of 900 mH and coefficient of coupling 0.5. The self inductance of each coils is

300 mH

150 mH

75 mH

50 mH

⇒ The signal to noise ratio in telemetry should be better than

5 db

10 db

25 db

60 db

⇒ Silicon and germanium have diamond structure. The number of atoms in a volume equal to

*a*

^{3}where

*a*is the edge of elementary cube are

32

16

8

4

⇒ As per Hall effect, if any specimen carrying a current I is applied in a transverse magnetic field B, then an electric field E is induced in the specimen in the direction.

parallel to I

perpendicular to B and parallel to I

parallel to I and B

perpendicular to both I and B

⇒ Which of the following statement about the amplitude limiter is not valid?

Leak type bias must be used

Output must be tuned

The circuit is always biased in class

*C*, by virtue of the leak type bias

When the input increases past the threshold of limiting, the gain decreases to keep the output constant

⇒

Match the following:

List I | List II | ||
---|---|---|---|

A. | R = 0 | 1. | Undamped oscillation |

B. | R < 2 L/C | 2. | Damped oscillation |

C. | R = 2 L/C | 3. | Critically damped response |

D. | R > 2 L/C | 4. | Non-oscillatory response. |

A-1, B-2, C-3, D-4

A-1, B-4, C-3, D-2

A-3, B-2, C-1, D-4

A-3, B-4, C-1, D-2

⇒ A copper atom is neutral. Its core has a net charge of

0

1

-1

2

⇒ Which of the following is not a valid logical expression in Pascal?

A > = B

A < = B

A = < B

A < > B

⇒ Directivity and beamwidth is related as

D ∝ B

D ∝ 1/B

D ∝ B

D ∝ B

^{2}

⇒ An amplifier has an input resistance of 10 kΩ and the noise voltage is 10 μV. If two such resistances of 10 kΩ each are connected in series at the input, the total noise voltage is about

20 μV

5μV

14.14 μV

10 μV

⇒

**Assertion (A):** A non-sinusoidal wave can be expressed in terms of sine waves of different frequencies which are multiples of the frequency of fundamental.

**Reason (R):** If negative half of a complex wave is a reproduction of the positive half, the even harmonics are absent.

Both A and R are correct and R is correct explanation of A

Both A and R are correct but R is not correct explanation of A

A is true, R is false

A is false, R is true

⇒ Super high frequency means more than 3000 MHz.

TRUE

FALSE

⇒

**Assertion (A):** The trigger circuit of a CRO is excited by the same signal as Y plates.

**Reason (R):** The time base generator develops a saw tooth voltage.

Both A and R are true and R is correct explanation of A

Both A and R are true but R is not correct explanation of A

A is true R is false

A is false R is true

⇒ For a 400 kHz transmission line having L = 0.5 mH/km, C = 0.08 mF and negligible R and G, the velocity propagation will be

15.8303 km/s

15.830 km/s

1.583 km/s

0.1583 km/s

⇒ If

*k*denotes Boltzmann's constant, the rms value of thermal noise voltage is proportional to

*k*

^{2}

*k*

*k*

(

*k*)

^{1/3}

⇒ The value of VSWR is taken as ∞ when the line is

short-circuited

open-circuited

terminated with full load

terminated with load equal to the characteristic impedance of the load

⇒ 1101

_{2}- 1001

_{2}=

1000

100

10

1

⇒ Choose proper substitutes for

*x*and

*y*to make the following statement corr

*x*: Reverse,

*y*: Reverse

*x*: Reverse,

*y*: forward

*x*: Forward,

*y*: Reverse

*x*: forward,

*y*: forward

⇒ The number of branches of root locus plot is equal to

the number of roots of characteristic equation

double the number of roots of characteristic equation

the number of roots of characteristic equation minus one

the number of roots of characteristic equation plus one

⇒ For a directional coupler the power is in the ratio of

40 dB

30 dB

20 dB

10 dB

⇒ The number of registers and flags in 8086 are

13 and 5 respectively

9 and 5 respectively

13 and 9 respectively

9 and 9 respectively

⇒ In figure, the short circuit current through terminal AB wil

1.5 A

0.125

0.0833333333333333

0.0416666666666667

⇒ The coil of a moving coil meter has 100 turns, is 40 mm long and 30 mm wide. The control torque is 240 x 10

^{-6}N-m on full scale. If

*B*= 1 Wb/m

^{2}, range of meter is

1 mA

2 mA

3 mA

4 mA

⇒ If the p and T circuits in figure are equivalent, then R

_{1}, R

_{2}, R

_{3}respectively

9 Ω, 6 Ω, 6 Ω

6 Ω, 6 Ω, 9 Ω

9 Ω, 6 Ω, 9 Ω

6 Ω, 9 Ω, 6 Ω

⇒ The amount of photoelectric emission current depends on the frequency of incident light.

TRUE

FALSE

⇒

`ALU 1C 74181`

can accept two words each having2 bits

4 bits

8 bits

16 bits

⇒ E

_{G}for silicon is 1.12 eV and that for germanium is 0.72 eV. Therefore, it can be concluded that

the conductivity of silicon will be less than that of germanium at room temperature

the conductivity of silicon will be more than that of germanium at room temperature

the conductivity of two will be same at 60°C

the conductivity of two will be same at 100°C