Question is ⇒ When V is the supply voltage and R is the rotor resistance per phase, the mechanical power developed by the synchronous motor will be proportional to, Options are ⇒ (A) <table class="tdfont"border="0" cellspacing="0"> <tr align="center"><td class="batta">V</td></tr> <tr align="center"><td >R</td></tr> </table> , (B) <table class="tdfont"border="0" cellspacing="0"> <tr align="center"><td class="batta">V<sup>2</sup></td></tr> <tr align="center"><td >R</td></tr> </table>, (C) <table class="tdfont"border="0" cellspacing="0"> <tr align="center"><td class="batta">R</td></tr> <tr align="center"><td >V<sup>2</sup></td></tr> </table>, (D) <table class="tdfont"border="0" cellspacing="0"> <tr align="center"><td class="batta">V</td></tr> <tr align="center"><td >R<sup>2</sup></td></tr> </table>, (E) , Leave your comments or Download question paper.

Question is ⇒ When V is the supply voltage and R is the rotor resistance per phase, the mechanical power developed by the synchronous motor will be proportional to, Options are ⇒ (A) <table class="tdfont"border="0" cellspacing="0"> <tr align="center"><td class="batta">V</td></tr> <tr align="center"><td >R</td></tr> </table> , (B) <table class="tdfont"border="0" cellspacing="0"> <tr align="center"><td class="batta">V<sup>2</sup></td></tr> <tr align="center"><td >R</td></tr> </table>, (C) <table class="tdfont"border="0" cellspacing="0"> <tr align="center"><td class="batta">R</td></tr> <tr align="center"><td >V<sup>2</sup></td></tr> </table>, (D) <table class="tdfont"border="0" cellspacing="0"> <tr align="center"><td class="batta">V</td></tr> <tr align="center"><td >R<sup>2</sup></td></tr> </table>, (E) , Leave your comments or Download question paper. Previous question Next question

Q1.

When V is the supply voltage and R is the rotor resistance per phase, the mechanical power developed by the synchronous motor will be proportional to

V²

R²

View Answer 10 -3

Explanation:-
Answer : B
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