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Q1. | What are the minimum number of 2 to 1 multiplexers required to generate a 2 input AND gate a 2 input Ex-OR gate? |

A. | 1 and 2 [Correct Answer] |

B. | 1 and 3 [Wrong Answer] |

C. | 1 and 1 [Wrong Answer] |

D. | 2 and 2 [Wrong Answer] |

View Answer
Explanation:-
Answer : ADiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ The main advantage of a crystal oscillator

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gives a high output voltage

frequency of oscillation is almost constant

can operates at a low dc voltage

⇒ In a minimum phase system

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all zeros lie in the left half plane

all poles lie in the right half plane

all except one pole or zero lie in the left half plane

⇒ For the circuit shown in the figure, D has a transition from 0 to 1 after CLK changes from 1 to 0. Assume gate delays to be neglig

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_{4}+ (101)

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