Question is ⇒ Typical values of current gains for CE, CB and CC amplifiers are, Options are ⇒ (A) 120, 120 and 1 respectively, (B) 120, 1 and 120 respectively, (C) 1, 120 and 120 respectively, (D) 1, 1 and 120 respectively, (E) , Leave your comments or Download question paper.

Question is ⇒ Typical values of current gains for CE, CB and CC amplifiers are, Options are ⇒ (A) 120, 120 and 1 respectively, (B) 120, 1 and 120 respectively, (C) 1, 120 and 120 respectively, (D) 1, 1 and 120 respectively, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	Typical values of current gains for CE, CB and CC amplifiers are
A.	120, 120 and 1 respectively [Wrong Answer]
B.	120, 1 and 120 respectively [Correct Answer]
C.	1, 120 and 120 respectively [Wrong Answer]
D.	1, 1 and 120 respectively [Wrong Answer]
View Answer 1 -1 Explanation:- Answer : B Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

Previous question Next question

Also Read Similar Questions Below :

⇒

Match the following:

	List I (Component)		List II (Dominant TE mode)
A.	Rectangular wave guide	1.	TE₁₀₁
B.	Circular waveguide	2.	TE₁₀
C.	Rectangular cavity	3.	TE₁₁₁
		4.	TE₁₁

A-4, B-2, C-1
A-2, B-1, C-3
A-3, B-4, C-1
A-2, B-3, C-1

⇒ A digital system is required to amplify a binary encoded audio signal. The user should be able to control the gain of the amplifier from a minimum to a maximum in 100 increments. The minimum number of bits required to encode, in straight binary is,
8
6
5
7

⇒ For a full wave bridge rectifier supplied with 50 Hz a.c., the lowest ripple frequency will be
50 Hz
100 Hz
200 Hz
400 Hz

⇒ A is even or B is true. Negation of above statement is
A is odd or B is false
A is odd and B is false
A is even or B is false
A is even and B is false

⇒ A potential of 7 V is applied to a silicon diode. A resistance of 1 K ohm is also in series with the diode. The current is
7 mA
6.3 mA
0.7 mA
0

⇒ Which one is a non-causal system?
y(n) = x(2n)
y(n) = x(n/2)
y(n) = x(n/2) + x(n)
all

⇒ The relative stability of a system is given by
gain margin alone
phase margin alone
both phase and gain margins
either (a) or (b)

⇒

Assertion (A): In SSB, carrier is suppressed by about 45 dB

Reason (R): SSB is standard form for radio communication

Both A and R are correct and R is correct explanation of A
Both A and R are correct but R is not correct explanation of A
A is correct but R is wrong
A is wrong but R is correct

⇒ The units of μ₀ and μ_r are
H/m for both
H/m for μ_r and no units for μ₀
H/m for μ₀ and no units for μ_r
Wb/m for μ₀ and no units for μ_r

⇒

Assertion (A): The function δ'(t - b) is equal to 0 for t ≠ b

Reason (R): A number of impulses spaced from one another form an impulse train.

Both A and R are correct and R is correct explanation of A
Both A and R are correct but R is not correct explanation of A
A is true, R is false
A is false, R is true

⇒ Consider the following stateme
1, 4 are correct
1 and 2 correct
1, 2, 3 are correct
2, 3, 4 are correct

⇒ To determine the polarity of voltage drop across a resistor, it is sufficient to know
direction of current through the resistor
direction and magnitude of current through the resistor
direction and magnitude of current and value of resistance
magnitude of current through the resistance

⇒ Consider the following statement associated with bipolar junction transistor and JFET

The former has higher input impedance than the later
The former has higher frequency stability than the later
The later has lower noise figure than the former
The later has higher power rating than the former.

Of these statements
1 and 2 are correct
2 and 3 are correct
3 and 4 are correct
1 and 4 are correct

⇒ The range of memory location in given memory interfacing scheme
0000H - 07FFH
F800H - FFFFH
0000H - 03FFH
0000H - 3FFFH

⇒ A waveguide section in a microwave circuit acts as
LP filter
Bandpass filter
HP filter
Band stop filter

⇒ The real part of complex frequency s corresponds to oscillations.
TRUE
FALSE

⇒ The approximate value of input impedance of CE amplifier with emitter resistance R_E is given by
h_ie + A_i R_E
h_ie + (1 + h_fe) R_E
h_ie
(1 + h_fe) R_E

⇒ Short-circuited stubs are used, because open-circuited stubs are
liable to radiate
complex in nature
providing open-circuit environments
unable to provide work over large frequency range

⇒ For the truth table of the given figure
A + B + C
A + BC
A
B

⇒ Refer to the NAND and NOR latches shown in the figure. The inputs (P₁, P₂) for both the latches are first made (0, 1) and then, after a few seconds, made (1, 1). The corresponding stable outputs (Q₁, Q₂)
NAND: first (0, 1) then (0, 1) NOR: first (1, 0) then (0, 0)
NAND: first (1, 0) then (1, 0) NOR: first (1, 0) then (1, 0)
NAND: first (1, 0) then (1, 0) NOR: first (1, 0) then (0, 0)
NAND: first (1, 0) then (1, 1) NOR: first (0, 1) then (0, 1)

⇒ If D is diameter of circular waveguide the cutoff wave-length for TE₁₁ mode is equal to
1.706 D
2.11 D
0.82 D
0.41 D

⇒ The frequency range for satellite communication is
3 to 30 kHz
300 to 3000 kHz
3000 to 30000 MHz
30000 to 300000 MHz

⇒ Figure shows a chopper feeding RLE load, The free wheeling diode conducts w
thyristor is on
thyristor is off
both when thyristor is on and thyristor is off
partly when thyristor is off and partly when thyristor is on

⇒ A network has 10 nodes and 17 branches. The number of different node pair are
7
9
10
45

⇒ The charge per proton is
1.6 x 10^-19 C
2.6 x 10^-19 C
0.6 x 10^-19 C
1.6 x 10^-13 C

⇒ In figure, V_{0-1 V
2 V
+1 V
+15 V}

⇒

Assertion (A): When a PID controller is added to a system, the peak overshoot to step input cannot be determined easily.

Reason (R): Use of PID controller introduces a zero in the forward path.

Both A and R are correct and R is correct explanation of A
Both A and R are correct but R is not correct explanation of A
A is correct but R is wrong
R is correct but A is wrong

⇒ Find the electric charge required on the earth and moon to balance their gravitational attraction if the charge on the earth is 10 times that on the moon.
1.73 TC
17.3 GC
17.3 TC
1.73 GC

⇒ For a sine wave the average value is calculated over half the cycle.
TRUE
FALSE

⇒ 10's complement of 16₁₀ is
83₁₀
84₁₀
38₁₀
48₁₀