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Q1. | To separate channels in FDM receiver we have to use |

A. | integration [Wrong Answer] |

B. | AND gate [Wrong Answer] |

C. | band pass filter [Correct Answer] |

D. | differentiation [Wrong Answer] |

View Answer
Explanation:-
Answer : CDiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ A signal is sampled at Nyquist rate

*f*= 2

_{s}*f*

_{0}. The function can be recovered from its samples only. If it is a

Periodic square wave of fundamental frequency

*f*

_{0}

Triangular wave of fundamental frequency

*f*

_{0}

Periodic sine wave of fundamental frequency

*f*

_{0}

Unit impulse function

⇒ Which statement is incorrect for the signal

*x*(

*t*) = 5 sin (2p x 10

^{3}

*t*) sin (2p x 10

^{6}

*t*)?

Upper side band frequency is 1001000

Carrier amplitude is 5

Lower sideband frequency is 990000

*x*(

*t*) is DSB-SC

⇒ The decimal equivalent of the binary number 10110.0101011101 is

22.24082165

22.340821675

22.3408213125

22.3408203125

⇒ It has been found that in a rectifier circuit with RC filter one RC section reduces ripple by 15%. Two RC sections are used in cascade the reduction in ripple would be

0.15

0.3

1.5

2.25

⇒ Find E at P(1, 1, 1) caused by four identical 3

*n*C point charges located at P

_{1}(1, 1, 0), P

_{2}(- 1, 1, 0), P

_{3}(- 1, - 1, 0) P

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21.58

*a*

*+ 21.58*

_{x}*a*

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_{y}*a*

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_{z}6.82

*a*

*+ 6.82*

_{x}*a*

*+ 32.89*

_{y}*a*

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_{z}-6.82

*a*- 6.82

_{x}*a*- 32.89

_{y}*a*V/m

_{z}-21.58

*a*- 21.58

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_{y}*az*V/m

⇒ In a Hurwitz polynomial

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both the odd and even parts have roots on

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the continued fraction expansion is the ratio of odd to even parts of a Hurwitz polynomial yields all positive quotient terms

all of the above

⇒ A voltage V(

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2

16

⇒ The hexadecimal number BBC7 is equivalent to decimal number

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46791

47691

49761

⇒ For a photoengraving the mask used is

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Iron-constantan

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Copper-constantan

Iron-silver

⇒ In a channel voice coder, the outputs of sixteen 20 Hz low pass filters are sampled, multiplexed and A/D converted. If sampling is at 40 samples/second and 3 bits/sample represents each voltage sample, the bit rate is about

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⇒ In figure, which value of Z

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⇒ If B, H and M denote flux density, field intensity and magnetisation, B = μ

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FALSE

⇒ 1011

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55

45

35

25

⇒ With respect to the Miller integrator sweep shown below, the sweep rate wil

2

4

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⇒ A 3 input NAND gate is to be used as inverter. Which of the following will give better results?

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⇒ In a series L-C circuit fed by ac voltage, voltage drops across L and C are 40 V and 30 V respectively. The supply voltage is

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50 V

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⇒ In a specimen of silicon steel, a field strength of 200 A/m causes a flux density of 0.5 T. In a specimen of cast iron, the same H would cause B to be

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0.5 T or more or less

⇒ In the given figure the input frequency is such that

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*v*

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*v*

_{i}by 90°

*v*

_{0}and

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⇒ Choose the function

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*t*< + ∞, for which a Fourier series cannot be defined

3 sin (25

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4 cos (20

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1

⇒ In a crystal

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the frequency of parallel resonance is more than frequency of series resonance

None of the above

⇒ Two meters X and Y require 40 mA and 50 mA for full scale deflection. Then

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⇒ The gauge factor of a semiconductor strain gauge is about

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⇒

**Assertion (A):** Inverters and choppers use fast switching thyristors

**Reason (R):** Fast switching SCR has low turn off time.

Both A and R are correct and R is correct explanation of A

Both A and R correct but R is not correct explanation of A

A is correct but R is wrong

A is wrong but R is correct

⇒

**Assertion (A):** In a parallel circuit having two branches, each branch current may be more than source current.

**Reason (R):** Calculations in ac circuits use rules of complex algebra.

Both A and R are true and R is correct explanation of A

Both A and R are true and R is not the correct explanation of A

A is true but R is false

A is false but R is true

⇒ An unmodulated voltage 10

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