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Q1. | The total area under the probability distribution curve is |

A. | 1 [Correct Answer] |

B. | 0 [Wrong Answer] |

C. | depend upon curve equation [Wrong Answer] |

D. | ∞ [Wrong Answer] |

View Answer
Explanation:-
Answer : ADiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ A (75 -

*j*50) Ω load is connected to a coaxial line of Z

_{0}= 75 Ω at 10 GHz. The best method of matching consists of using

a capacitance at some specific distance from load

a short circuited stub at some specific distance from load

an inductance at load

a short circuited stub at load

⇒ An RLC series circuit has R = 7.07 Ω, L = .707 H and C = 7.07 μF. At Half power frequencies the circuit impedance is likely to be

7.07 Ω

10 Ω

14.14 Ω

20 Ω

⇒ Which mode has the minimum cutoff frequency in rectangular wave guides?

TE

_{11}

TE

_{10}

TE

_{01}

TE

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⇒ Which dc servomotor has minimum inertia?

Slotted armature construction

Surface wound armature

Surface wound with stationary rotor

Either (a) or (b)

⇒ The flow rate of electrically conducting liquid without any suspended particle can not be measured by

turbine flow meter

electromagnetic flow meter

ultrasonic flow meter

thermistor based heat flow meter

⇒ If

*f*(

*t*) = -

*f*(-

*t*) and

*f*(

*t*) satisfies Dirichlet conditions, then

*f*(

*t*) can be expanded in Fourier series having

sine terms only

cosine terms only

cosine and constant terms

sine and constant term

⇒ The box on the external left of the title bar of menu is called control menu box.

TRUE

FALSE

⇒ In a driving point function poles and zeros must be conjugate if complex or imaginary.

TRUE

FALSE

⇒ The oscillator shown in figure

Colpitt's oscillator

Hartley oscillator

Tuned emitter oscillator

Clapp oscillator

⇒ Two capacitors each of capacitance C and breakdown voltage V are joined in series. The capacitance and breakdown voltage of the combination is

0.5 C and 2 V

0.5 C and 0.5 V

C and V

2 C and 2 V

⇒

*c*(

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*m*(

*t*) are used to generate an AM signal. The modulation index of the generated AM signal is 0.5 then the quant

42737

42739

42738

42743

⇒ For a current transformer, the standard secondary rating is

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2.5 A

0.416666666666667

5 A or 10 A

⇒ Commercial ECL gates use two ground lines and one negative supply to

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increase fan out

reduce loading effect

eliminate the effect of power line glitches on the biasing circuit

⇒

**Assertion (A):** As per Miller theorem a capacitance C from input to output appears as a much larger capacitance across input terminals

**Reason (R):** In a lag network the output voltage appears across capacitor

Both A and R are correct and R is correct explanation for A

Both A and R are correct but R is not correct explanation for A

A is correct R is wrong

A is wrong R is correct

⇒

Match the following:

List I | List II | ||
---|---|---|---|

A. | LED | 1. | Heavy Doping |

B. | Avalanche Photodiode | 2. | Coherent Radiation |

C. | Tunnel diode | 3. | Spontaneous Emission |

D. | LASER | 4. | Current gain |

A-2, B-4, C-3

A-2, B-3, C-1, D-4

A-3, B-4, C-1, D-2

A-2, B-1, C-4, D-3

⇒ In a synchro transmitter-control transformer, the voltage induced in rotor winding of control transformer is zero when the angular displacement between rotors of transmitter and transformer is

0°

90°

180°

either (a) or (c)

⇒ In a BJT amplifier the power gain from base to collector is 4000. The power gain in dB is

3.6

36

7.2

72

⇒ The Boolean expression A ⊕ B is equivalent to

AB + AB

AB + AB

B

A

⇒ The voltage gains of an amplifier without feedback and with negative feedback respectively are 100 and 20. The percentage of negative feedback (β) would be

0.4

0.05

0.2

0.8

⇒ The circuit show

voltage series feedback amplifier

transconductance amplifier

transresistance amplifier with open circuit mutual resistance R

_{F}

transresistance amplifier with short circuit mutual resistance R

_{F}

⇒ Which interrupts are masked?

5.5

6.5

7.5

None

⇒ Consider the following

line 25

line 35

any of the lines 15 or 25, 35

⇒ Probability of error in DPSK is less than PSK

TRUE

FALSE

equal

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⇒ When P-N junction is in forward bias, by increasing the battery voltage

current through P-N junction reduces

current through P-N junction increases

circuit resistance increases

none of the above

⇒ The gate lead, in a thyristor is welded to :

*p*layer to which anode is connected

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*p*layer nearest to the cathode terminal

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*n*layer

⇒ The minimum number of equations required to analyze the circuit shown in the figur

3

4

6

7

⇒ Find the output voltage for 011100 in a 6 bit R-2

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2.84 V

0.1 V

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⇒ A CE amplifier has a high input signal. In the wave shape of emitter current

positive and negative half cycles will be symmetrical

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positive half cycle will be compressed and negative half cycle will be elongated

the half cycles may be either elongated or compressed

⇒ A two branch parallel tuned circuits has a coil of resistance R and inductance L in one branch and capacitance C in the second branch. The bandwidth is 200 radians/sec. A load of resistance R

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200 rad/sec

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less than 200 rad/sec

200 rad/sec or less

⇒ At absolute zero temperature a semiconductor behaves like

an insulator

a super conductor

a good conductor

a variable resistor