Users Also Read

MCQ's Search Engine

Electrical Engineering

Mechanical Engineering

Civil Engineering

Automobile Engineering

Chemical Engineering

Computer Engineering

Electronics Engineering

Medical Science Engg

Q1. | The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages was 34. The ages of the son and the father are respectively: |

A. | 6 & 39 [Correct Answer] |

B. | 7 & 38 [Wrong Answer] |

C. | 9 & 36 [Wrong Answer] |

D. | 11 & 34 [Wrong Answer] |

View Answer
Explanation:-
Answer : ADiscuss it below :Let the father age be x years and son age be y yearsGiven : The sum of the ages of father and his son is 45 years X + y = 45 ----------------(1) Given : 5 years ago, the product of their ages was 34 years (x-5) (y-5) = 34 ---------(2) From (1), y = 45 – y ; (2) becomes(x-5) (40-x) = 34 40x –x ^{2}-200 + 5x =34-x ^{2}+45x – 200 – 34 = 0x ^{2}– 45x +234 = 0 (234 = 39 x 6 )x-39; x-6 Put x = 39 in (1) Y = 6 Therefore father’s age is 39 years and Son’s age is 6 years !! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand’s present age in years?

24

27

40

None of these

⇒ Six years ago, the ratio of the ages of Kunal and Sagar was 6:5. Four years hence, the ratio og their ages will be 11:10. What is Sagar's age at present?

16 years

18 years

20 years

None of these

⇒ The present ages of three persons are in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

8, 20, 28

16, 28, 36

20, 35, 45

None of these

⇒ After 5 years, age of neelam would be 28 years, what was her age 8 years ago ?

15

20

25

30

⇒ The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:

5:2

7:3

9:2

13:4

⇒ Six years ago, the ratio of the ages of Akash and vipul was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is vipul's age at present?

18

17

16

15

⇒ Ayesha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents ?

2 years

4 years

6 years

8 years

⇒ Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit’s age. After further 8 years, how many times would he be of Ronit’s age?

2 times

2(1/2) times

2(3/4) times

3 times

⇒ One year ago, Promila was four times as old as her daughter Sakshi. Six years hence, Promila's age will exceed her daughter's age by 9 years. The ratio of the present ages of Promila and her daughter is:

9:2

11:3

12:5

13:4

⇒ The ratio of the present age of two brothers is 1:2 and 5 years back, the ratio was 1:3. What will be the ratio of their ages after 5 years?

1:4

2:3

3:5

5:6

⇒ The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A?

12

24

C is elder than A

None of these

⇒ A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is:

14 years

18 years

20 years

22 years

⇒ A wizard named Nepo says "I am only three times my son's age. My father is 40 years more than twice my age. Together the three of us are a mere 1240 years old." How old is Nepo?

360

240

120

480

⇒ Thirteen years back, my mother was thrice my age and two years back, she was twice my age. Find my mother’s present age.

58

46

28

24

⇒ The ratio of the age of a man and his wife is 4:3. At the time of marriage the ratio was 5:3 and After 4 years this ratio will become 9:7. How many years ago were they married?

14 years

10 years

12 years

8 years

⇒ Sandeep's age after six years will be three-seventh of his father's age. Ten years ago the ratio of their ages was 1 : 5. What is Sandeep's father's age at present?

30

40

50

60

⇒ The sum of ages of father and his son is 45 years. Five years ago, the product of their ages was 34. The ages of the son and the father are respectively:

6 and 39

7 and 38

9 and 36

11 and 34

⇒ The age of a man is three times the sum of the ages of his two sons. Five years hence, his age will be double of the sum of the ages of his sons. The father's present age is:

40 years

45 years

50 years

55 years

⇒ Five years ago, the sum of my age and my mother's age was equal to my father's age. If my father is 6 years elder than my mother, find my present age.

12

11

10

6

⇒ The present ages of P,Q and R are in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. What are their present ages (in years)?

Insufficient data

16,30,40

16,28,40

16.28,36

⇒ The difference between the ages of A and C is half the age of B. The difference between the ages of A and B is one-sixth of the age of C. If the sum of the ages of B and C is 32, find the age of A.

25

22

20

27

⇒ P is two years older than Q who is twice as old as R. The total of the ages of P, Q and R is 27. How old is Q?

10

9

8

7

⇒ A person's present age is two fifth of the age of his mother.After 8 years, he will be one-half of the age of his mother. How old is the mother at present?

32 years

36 years

40 years

48 years

⇒ The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is ?

5 : 2

7 : 3

9 : 2

13 : 4

⇒ A person was asked state his age in years. His reply was, “Take my age three years hence, multiply it by 3 and then subtract three times my age three years ago and you will know how old I am”. What was the age of the

person?

18 years

20 years

224 years

32 years

⇒ The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age will be twice that of his son. The ratio of their present ages is:

5 : 2

7 : 3

9 : 2

13 : 4

⇒ The present ages of Ram and Raj differ by 7. Five years back, Raj was twice the age of Ram. Find the age of Ram after 4 years.

16

20

21

25

⇒ Ayisha's age is 1/6th of her father's age. Ayisha 's father's age will be twice the age of Shankar's age after 10 years. If Shankar's eight birthdays was celebrated two years before, then what is Ayisha 's present age.

10 years

8 years

5 years

12 years

⇒ Father is aged three times more than his son Alok. After 8 years, he would be two and a half times of Alok's age. After further 8 years, how many times would he be of Alok's age?

4 times

6 times

2 times

3 times

⇒ The sum of the ages of Lily and Nancy is twice the difference of their ages. Find the ratio of Nancy's age to Lily's age.

1:3

3:1

1:2

2:1