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Q1. | The sum of the ages of a father and his son is 45 years. Five years ago, the product of their ages was 34. The ages of the son and the father are respectively: |

A. | 6 & 39 [Correct Answer] |

B. | 7 & 38 [Wrong Answer] |

C. | 9 & 36 [Wrong Answer] |

D. | 11 & 34 [Wrong Answer] |

View Answer
Explanation:-
Answer : ADiscuss it below :Let the father age be x years and son age be y yearsGiven : The sum of the ages of father and his son is 45 years X + y = 45 ----------------(1) Given : 5 years ago, the product of their ages was 34 years (x-5) (y-5) = 34 ---------(2) From (1), y = 45 – y ; (2) becomes(x-5) (40-x) = 34 40x –x ^{2}-200 + 5x =34-x ^{2}+45x – 200 – 34 = 0x ^{2}– 45x +234 = 0 (234 = 39 x 6 )x-39; x-6 Put x = 39 in (1) Y = 6 Therefore father’s age is 39 years and Son’s age is 6 years !! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

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