Question is ⇒ The runway length after correcting for elevation and temperature is 2845 m. If the effective gradient on runway is 0.5 percent then the revised runway length will be, Options are ⇒ (A) 2845 m, (B) 2910 m, (C) 3030 m, (D) 3130m, (E) , Leave your comments or Download question paper.

Question is ⇒ The runway length after correcting for elevation and temperature is 2845 m. If the effective gradient on runway is 0.5 percent then the revised runway length will be, Options are ⇒ (A) 2845 m, (B) 2910 m, (C) 3030 m, (D) 3130m, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	The runway length after correcting for elevation and temperature is 2845 m. If the effective gradient on runway is 0.5 percent then the revised runway length will be
A.	2845 m [Wrong Answer]
B.	2910 m [Wrong Answer]
C.	3030 m [Correct Answer]
D.	3130m [Wrong Answer]
View Answer 11 -25 Explanation:- Answer : C Discuss it below : Gantasala harish Said on 2018-10-29 23:46:42 Correction for gradient = (20/100)x2845x0.5 = 284 m. Corrected runway length = 2845+284 = 3130 m. Partha Said on 2017-07-26 09:20:49 Plz explain !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

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