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Q1. | The runway length after correcting for elevation and temperature is 2845 m. If the effective gradient on runway is 0.5 percent then the revised runway length will be |

A. | 2845 m [Wrong Answer] |

B. | 2910 m [Wrong Answer] |

C. | 3030 m [Correct Answer] |

D. | 3130m [Wrong Answer] |

View Answer
Explanation:-
Answer : CDiscuss it below :Gantasala harish Said on 2018-10-29 23:46:42Correction for gradient = (20/100)x2845x0.5 = 284 m. Partha Said on 2017-07-26 09:20:49Plz explain !! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

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