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Q1. | The r.m.s. value of a sinusoidal A.C. current is equal to its value at an angle of____ degrees |

A. | 90 [Wrong Answer] |

B. | 60 [Wrong Answer] |

C. | 45 [Correct Answer] |

D. | 30 [Wrong Answer] |

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Explanation:-
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⇒ Power factor of electric bulb is

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Lagging

Leading

Unity

⇒ Higher the Q of a series circuit

Broader its resonance curve

Narrower its pass band

Greater its band width

Sharper its resonace

⇒ The peak value of a sine wave is 200 V. Its average value is

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⇒ The r.m.s. value of a sine wave is 100A. Its peak value is

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⇒ For 200 V r.m.s. value triangular wave, the peak voltage will be

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346 V

⇒ The dual of a link is

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Loop

Tree branch

⇒ The ratio of the bandwidth to the resonance frequency is called the____ of the circuit.

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⇒ The dual of a loop is

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Mesh

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⇒ While drawing vector diagram for a series circuit the reference vector is

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⇒ In an A.C. circuit I sin Φ is called

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None of these

⇒ For the same peak value which of the following wave will have the highest r.m.s. value ?

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Half wave rectified sine wave

Triangular wave

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⇒ A heater is rated as 230 V, 10 KW, AC. The value 230 V refers t

Average voltage

r.m.s. voltage

Peak voltage

None of these

⇒ The negative maximum of a cosine wave occurs at

30

45

90

180

⇒ The r.m.s. value and mean value is the same in the case of

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Half wave rectified sine wave

⇒ Capacitors for power factor correction are rated in

kW

kVA

kV

kVAR

⇒ For a sine wave with peak value I

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0.707 I

_{max}

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Leads

Remains in phase with

None of the above

⇒ A parallel resonant circuit can be used

As a high impedance

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Both (A) and (B)

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⇒ Inductance affects the direct current flow

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Only at the time of turning on

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⇒ In a series resonant circuit, the impedance of the circuit is

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⇒ In the R - L - C containing R = 4.5ω L = 0.06 H,C = 0.6 µF the power factor will be

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Reduction in power losses

Reduction in load handling capacity of electrical system

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Current leads the voltage by 90°

Current can lead or lag the voltage by 90°

Current is in phase with the voltage

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