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Q1. | The minimum step size required for a Delta modulator operating at 36 samples/sec to track the signal (here u(t) is the unit step function) x(t) = 125t (u(t) - u(t - 1)) + (250 - 125t) (u(t - 1) - u(t - 2)) So that slope overload is avoided, would be |

A. | 2^{-10} [Wrong Answer] |

B. | 2^{-8} [Correct Answer] |

C. | 2^{-6} [Wrong Answer] |

D. | 2^{-4} [Wrong Answer] |

View Answer
Explanation:-
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