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Q1. | The method of virtual work in the analysis of structures results is |

A. | Compatible deformations [Wrong Answer] |

B. | Equilibrium of forces [Correct Answer] |

C. | Stress strain relations [Wrong Answer] |

D. | None of these [Wrong Answer] |

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Explanation:-
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**Also Read Similar Questions Below :**

⇒ A load 'W is moving from left to right support on a simply supported beam of span T. The maximum bending moment at 0.4 1 from the left support is

0.16 Wl

0.20 Wl

0.24 Wl

0.25 Wl

⇒ Effects of shear force and axial force on plastic moment capacity of a structure are respectively to

increase and decrease

increase and increase

decrease and increase

decrease and decrease

⇒ In column analogy method, the area of an analogous column for a fixed beam of span L and flexural rigidity El is taken as

L/EI

L/2EI

L/3EI

L/4EI

⇒ For earthquake resistant masonry buildings, where seismic coefficient is less than 0.08, the horizontal distance between two openings shall not be less than

Vt x height of shorter opening

Vt x height of longer opening

Ax height of shorter opening

Vi x height of longer opening

⇒ Independent displacement components at each joint of a rigid-jointed plane frame are

three linear movements

two linear movements and one rotation

one linear movement and two rotations

three rotations

⇒ In the case of panel wall subjected to horizontal loads at right angles to the plane of the wall, with the mortar not leaner than Ml type, tensile stress in bending in the vertical direction may be allowed to the extent of

0.4 kg/cm2

0.7 kg/cm2

1.0 kg/cm2

1.2 kg/cm2

⇒ The stiffness method in structural analysis is also known as

Unit load method

Consistent deformation method

Force method

Displacement method

⇒ Which of the following is not the displacement method ?

Equilibrium method

Column analogy method

Moment distribution method

Kani's method

⇒ The timber floor not spanning on the masonry wall but properly anchored to the wall gives

lateral restraint but not rotational restraint

rotational restraint but not lateral restraint

both lateral and rotational restraints

neither lateral nor rotational restraint

⇒ If there are m unknown member forces, r unknown reaction components and j number of joints, then the degree of static indeterminacy of a pin-jointed plane frame is given by

m + r + 2j

m - r + 2j

m + r - 2j

m + r - 3j

⇒ In moment distribution method the sum of distribution factors of all the members meeting at any joint is always

Zero

< 1

> 1

= 1

⇒ Minimum thickness of stiffening wall for 1 to 3 storeys shall not be less than

10 cm

15 cm

20 cm

30 cm

⇒ Weaker mortar. Of these statements

2 and 3 are correct

1 and 2 are correct

1 and 3 are correct

1, 2 and 3 are correct

⇒ Principle of superposition is applicable when

deflections are linear functions of applied forces

material obeys Hooke's law

the action of applied forces will be affected by small deformations of the structure

none of the above

⇒ The mode of failure of a very short masonry member having h/t ratio of less than 4 is by

shear

vertical tensile splitting

buckling

any of the above

⇒ Unequal settlements in the supports of a statically indeterminate structure develop

Member forces

Reactions from supports

No reactions

Strains in some members only

⇒ The degree of static indeterminacy up to which column analogy method can be used is

2

3

4

unrestricted

⇒ A simply supported beam deflects by 5 mm when it is subjected to a concentrated load of 10 kN at its centre. What will be deflection in a 1/10 model of the beam if the model is subjected to a 1 kN load at its centre ?

5 mm

0.5 mm

0.05 mm

0.005mm

⇒ To generate the j th column of the flexibility matrix

a unit force is applied at coordinate j and the displacements are calculated at all coordinates

a unit displacement is applied at co-ordinate j and the forces are calculated at all coordinates

a unit force is applied at coordinate j and the forces are calculated at all coordinates

a unit displacement is applied at co-ordinate j and the displacements are calculated at all co-ordinates

⇒ The deformation of a spring produced by a unit load is called

stiffness

flexibility

influence coefficient

unit strain

⇒ If the horizontal cross-sectional area of a wall is 1200 cm2, then the basic stress shall be multiplied by a reduction factor equal to

0 6

0.75

0.85

0.95

⇒ Which of the following methods of structural analysis is a displacement method ?

moment distribution method

column analogy method

three moment equation

none of the above

⇒ Degree of kinematic indeterminacy of a pin-jointed plane frame is given by

2j - r

j - 2r

3j - r

2j + r

⇒ The Castigliano's second theorem can be used to compute deflections

in statically determinate structures only

for any type of structure

at the point under the load only

for beams and frames only

⇒ For masonry built in 1:1:6 cement-lime-sand mix mortar or equivalent, the horizontal shear stress permissible on the area of a mortar bed joint is

0.15 MPa

0.125 MPa

0.1 MPa

0.075 MPa

⇒ The carryover factor in a prismatic member whose far end is fixed is

0

1/2

3/4

1

⇒ The basic stress in masonry units having height to width ratio of 1.5 may be increased by a factor of

1.2

1.4

1.6

2.0

⇒ The moment distribution method in structural analysis can be treated as

Force method

Displacement method

Flexibility method

None of these

⇒ Direct load carrying capacity of a brick masonry wall standing freely as against when it supports RC slab will be

more

less

the same in both the cases

100%

⇒ Which of the following will give higher ratio of brickwork strength to mortar strength ?

1 : % : 3

1 : Vz: 4>/2

1:1:6

1:2:9