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Q1. | The maximum effective aperture of λ/2 (half-wave) antenna is |

A. | 0.013 λ^{2} [Wrong Answer] |

B. | 0.13 λ^{2} [Correct Answer] |

C. | 1.3 λ^{2} [Wrong Answer] |

D. | 13 λ^{2} [Wrong Answer] |

View Answer
Explanation:-
Answer : BDiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ A transmitted using AM has in modulated carrier output power of 10 KW and can be modulated to a maximum depth of 90% by a sinusoidal modulating voltage without causing overloading. Find the value to which an modulated carrier power can be increased without resulting in overloading if the maximum permitted modulating index is 40%

14 KW

12.96 KW

26.96 KW

2.96 KW

⇒ The magnitude plot of a composite signal

*x*(

*t*) =

*e*

^{2jt}+

*e*

^{3jt}is

Half wave rectified sinusoid

Full wave rectified sinusoid

Exponentially increasing sinusoid

Exponentially decreasing sinusoid

⇒ Consider the following statement in B

200, 250, 150 respectively

150, 200, 250 respectively

250, 200, 150 respectively

200, 150, 250 respectively

⇒ A loop antenna may be of

square on triangular shape

hexagonal shape

circular shape

any of the above

⇒ If V

_{r}is the reverse voltage across a graded P-N Junction, then the junction capacitance

*c*

_{j}is proportional to

(V

_{r})

^{2}

(V

_{r})

^{n}

(V

_{r})

^{-n}

(V

_{r})

^{3/2}

⇒ Trinitron is a monochrome picture tube.

TRUE

FALSE

⇒ Class A and class B chopper

operate in first quadrant

operate in second quadrant

class A chopper operates in first quadrant while class B operates in second quadrant

may operate in either first or second quadrant

⇒ In the FM wave described by equation

*v*= 15 sin (4 x 10

^{8}

*t*+ 3 sin 1100

*t*), the maximum frequency deviation is

175 Hz

525 Hz

3 Hz

58.33 Hz

⇒ Two coupled coils lie in parallel planes such that 50% of magnetic flux produced by one links the other. The coefficient of coupling is

0.5

0.25

0.125

0.5

⇒ Which of them contains an organic fluid?

LED

LCD

Both LED and LCD

Neither LED nor LCD

⇒ Modulation is also called detection.

TRUE

FALSE

⇒ Modified Mc Murray full bridge inverter uses

4 thyristors and 2 diodes

4 thyristors and 4 diodes

8 thyristors and 4 diodes

8 thyristors and 8 diodes

⇒ 4 point DFT for

*x*(

*n*) = {2, - 1, 2, 3} is

{6, 4 - 2

*j*, 2, 2

*j*}

{6, 4

*j*, 2, - 4

*j*}

{6, -1 + 3

*j*, 4 - 4

*j*, 4 - 2}

{6, 2

*j*, 4 - 2

*j*, - 2 + 2

*j*}

⇒ It is very likely in __________ gate family that when one gate is driving number of gates in __________ , a gate having least voltage for saturation may consume large __________ leaving other gates inoperative and this phenomenon is called __________ .

DTL, parallel, current, current - sinking

DCTL, parallel, current, current-lagging

ECL, series, voltage, voltage-deterioration

DCTL, series, current, current-lagging

⇒ Foster Seeley discriminator uses a

single tuned circuit

double tuned circuit with primary and secondary tuned to the same frequency

double tuned circuit with primary and secondary tuned to the different frequency

none of the above

⇒ If a dipole is meant for a frequency of 1 MHz, the length of each rod is about

5 m

20 m

100 m

50 m

⇒ If the operating temperature increases by 10°C, the rate of deterioration of solid dielectric becomes

double

one and a half time

3 times

4 times

⇒ The pre-emphasis in FM aids in providing extra noise immunity by

emphasizing only the higher frequency components

emphasizing the entire frequency band

emphasizing only the lower frequency band

cutting down the low frequency noise

⇒ Which of the following is best suited for parity checking and parity generation?

AND, OR, NOT gates

XOR, Exclusive NOR gate

NAND gates

NOR gates

⇒ A 3 phase semiconverter when supplying a certain load has a rectification efficiency of 0.6 and transformer utilisation factor of 0.35. When a 3 phase full converter is supplying the same load

rectification efficiency will be more than 0.6 and TUF will be more than 0.35

rectification efficiency will be more than 0.6 but TUF will be less than 0.35

rectification efficiency will be less than 0.6 and TUF will be less than 0.35

rectification efficiency will be less than 0.6 but TUF will be more than 0.35

⇒ The gap width in audio heads is about 0.01 mm.

TRUE

FALSE

⇒

**Assertion (A):** At room temperature the fermi level in *p* type semiconductor lies nearer to the valence band and in *n* type semiconductor it lies nearer to the conduction band.

**Reason (R):** At room temperature, the *p* type semiconductor is rich in holes and *n* type semiconductor is rich in electrons.

Both A and R are true and R is correct explanation of A

Both A and R are true but R is not a correct explanation of A

A is true but R is false

A is false but R is true

⇒ Tracking of extra terrestrial objects requires

high transmitting power

very sensitive receiver

fully steerable antenna

all of the above

⇒

Match the following:

List I | List II | ||
---|---|---|---|

A. | PMMC | 1. | Square law type scale |

B. | Moving iron | 2. | Very good response |

C. | Thermo-couple | 3. | Linear scale |

D. | Electrostatic | 4. | Voltmeter |

A-4, B-1, C-2, D-3

A-3, B-2, C-1, D-4

A-4, B-2, C-1, D-3

A-3, B-1, C-2, D-4

⇒ In a flip-flop with

*RS*latch a high

*S*and a low

*R*set the output to __________ and a low

*S*and a high

*R*set the output __________ .

low, low

high, high

low, high

high, low

⇒ In AM increased depth of modulation increases __________ and in FM with increased depth of modulation __________ increases.

total transmitted power, bandwidth

bandwidth, bandwidth

bandwidth, total transmitted power

total transmitted power, sideband power

⇒ Varactor diode is forward biased when it is used.

TRUE

FALSE

⇒ The nodal method of circuit analysis is based on

KVLs, ohm law

KCLs, ohm law

KCLs, KVL

KCL, KVL, ohms law

⇒ Algebraic expression for

*z*-transform of

*x*[

*n*] is X[

*z*]... What is the algebraic expression of

*z*-transform of

*e*

^{jω0n}

*x*[

*n*]?

X(Z - Z

_{0})

X(

*e*

^{-jW0z})

X(

*e*

^{jω0z})

X(Z)

^{jω0z}

⇒ When sources of different frequencies feed a network the only method of solution is superposition theorem.

TRUE

FALSE