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Q1. | The main advantage of hexadecimal numbers is |

A. | ease of conversion from hexadecimal to binary and vice-versa [Correct Answer] |

B. | ease of conversion from hexadecimal to decimal and vice-versa [Wrong Answer] |

C. | ease of conversion from gray code to binary and vice-versa [Wrong Answer] |

D. | the use of numbers and alphabets [Wrong Answer] |

View Answer
Explanation:-
Answer : ADiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒

Match the following:

List I (Set operation) | List II (Set operator) | ||
---|---|---|---|

A. | Set equality | 1. | - |

B. | Set inclusion | 2. | = |

C. | Set intersection | 3. | < = |

D. | Set difference | 4. | ∗ |

A-2, B-3, C-4, D-1

A-3, B-2, C-4, D-1

A-1, B-2, C-3, D-4

A-4, B-2, C-3, D-1

⇒ Whenever a JFET operates above pinch-off voltage

depletion regions become smaller

drain current increase steeply

drain current starts decreasing

drain current remains nearly constant

⇒ A rectangular waveguide (2.29 x 1.02) cm operates at a freq. of 11 GHz in TE

_{10}mode. If the maximum potential gradient of the signal is 5 kV/cm, then the maximum power handling capacity of the waveguide will be

31.11 mW

31.11 W

31.11 kW

31.11 MW

⇒ Eddy current loss is

proportional to frequency

independent of frequency

proportional to (frequency)

^{2}

proportional to (frequency)

^{3}

⇒ The addition of

*n*type impurity to intrinsic material creates allowable energy levels.

slightly below conduction band

slightly above conduction band

slightly below valence band

slightly above valence band

⇒ For most metals, Fermi level E

_{F}is less than

0.1 eV

2 eV

5 eV

10 eV

⇒ As compared to tuned radio frequency receivers which of the following is the advantage of using superheterodyne receivers?

High gain and better sensitivity

Better selectivity at high frequencies

Stability

Noise suppression

⇒ The current through a 1 mH inductance is

*i*(

*t*) = 2.56 x 10

^{-2}- 4 x 10

^{3}

*t*for 2 ≤

*t*≤ 20 μ sec. The voltage across the inductor is

4

8

0

8 x 10

^{3}

⇒ Consider the following statements about transport-lag

- It is of non-minimum phase behaviour
- It normally exists in thermal, hydraulic and pneumatic systems
- It has an excessive phase lag with no attenuation at high frequency

1 only

1 and 2

All

2 and 3

⇒ LCD uses

nematic crystals

sematic crystals

cholesteric crystals

twisted nematic crystal

⇒ Consider the following library functions

- EXP (
*i.e., e*^{x}) - ARCTAN (
*i.e.* tan^{-1} *x*) - SQRT (
*i.e., x*) - AES (
*i.e. *|*x*|) <

All

1 and 3 only

1, 3, 4 only

1, 2 and 3 only

⇒ Which of the following transducers requires a high input impedance preamplifier for proper measurements?

Thermocouple

Piezoelectric

Thermistor

L.V.D.T

⇒ In a digital system, the maximum clock frequency that can be used with Master/Slave Clocked flip-flops having total propagation delay of 200 μsec is

20 MHz

50 MHz

100 MHz

200 MHz

⇒ The operations which occur most frequently in a computer are

fetch

execute

both (a) and (b)

none of the above

⇒ Decimal 8 in excess-3 code =

1000

1001

1011

1111

⇒ One can format a disc using window explorer.

TRUE

FALSE

⇒ For very low frequencies, log magnitude for the given figur

0 dB

-3 dB

3 dB

10 dB

⇒ A specimen of a material has a resistivity of 1.78 x 10^{8} ohm-m. The material is

semiconductor

conductor

semiconductor or conductor

insulator

⇒ Which one of the following is transferred locking electron device *C* antenna?

BARITT diode

IMPATT diode

Gunn diode

Step recovery diode

⇒ Which of the following is a valid expression in FORTRAN 77?

B * - 3

B * (- 3)

B * * - 3

B * + 2

⇒ A voltage wave *v* = 10 + 20 sin ω*t* + 7.5 sin 3 ω(*t*) is applied to a series combination of two elements. The current is *i* = 5 sin (ω*t* + 20°) + 1.5 sin (3ω*t* + 10°). The elements are

R and C

R and L

L and C

both inductances

⇒ Find R_{TH200 Ω0 Ω400 ΩNone of these}

⇒ In the given figure R_{C} = R_{L} = 1 kΩ, then V_{05 V2.5 V1 V0 V}

⇒ A step voltage E is applied to an R-L series circuit. At *t* = 0, the current in the circuit is

E/R

E/L

infinity

zero

⇒ In spread spectrum technique

a modulated signal is modulated again

a modulated signal is modulated twice again

the power of a modulated signal is increased

the noise component of a modulated signal is decreased

⇒ Figure represen

Diode rectifier

Schottky diode

Varistor

None of the above

⇒ D/A converters are generally

weighted resistor network

binary ladder network

either (a) or (b)

neither (a) nor (b)

⇒ The current due to thermionic emission is proportional to

T

T^{2}

T^{3}

T^{4}

⇒ If a electromagnetic signal is incident at 0° in a waveguide then at other port of waveguide we will get

zero power

∞ power

depend upon input signal strength

depend on frequency

⇒ Following figure repres

AND

OR

NAND

NOT

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