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Q1. | The inputs A, B, C of the given figure are applied to a 3 input NOR gate. The outpu |

A. | HIGH from 4 to 0 [Wrong Answer] |

B. | LOW from 0 to 4 [Wrong Answer] |

C. | HIGH from 0 to 1 and LOW from 1 to 4 [Correct Answer] |

D. | LOW from 0 to 2 and HIGH from 2 to 4 [Wrong Answer] |

View Answer
Explanation:-
Answer : CDiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ In which of the following logical group instructions of 8085 do the contents of accumulator remain unchanged?

`ORA `*r*

`ORA M`

`ORI data`

`CMP `*r*

⇒

**Assertion (A):** The dual of a circuit can be drawn by window-dot method.

**Reason (R):** The principle of duality is of great help in circuit analysis.

Both A and R are true and R is correct explanation of A

Both A and R are true and R is not the correct explanation of A

A is true but R is false

A is false but R is true

⇒ Each cell of a static RAM has

4 MOS transistors

4 MOS transistors and 2 capacitors

2 MOS transistors and two capacitors

1 MOS transistor and 1 capacitor

⇒ The carriers of

*n*channel JFET are

free electrons and holes

holes

free electrons or holes

free electrons

⇒ At room temperature a semiconductor material is

perfect insulator

conductor

slightly conducting

any of the above

⇒ For plane wave propagating in free space or two conductor transmission line, what must be the relationship between the phase velocity

*v*, the group velocity

_{p}*v*and speed of light

_{g}*c*?

*v*>

_{p}*c*>

*v*

_{g}*v*<

_{p}*c*<

*v*

_{g}*v*=

_{p}*c*=

*v*

_{g}*v*<

_{p}*v*<

_{g}*c*

⇒ The main advantage of hexadecimal numbers is

ease of conversion from hexadecimal to binary and vice-versa

ease of conversion from hexadecimal to decimal and vice-versa

ease of conversion from gray code to binary and vice-versa

the use of numbers and alphabets

⇒ The unit of loudness is

phon

sone

decibel

mel

⇒ As the temperature of an intrinsic semiconductor material is increased

protons get excited

neutrons acquire charge

energy of the atom is increased

additional holes are created in the conduction band

⇒ A resistance of 5 ohms is connected in one branch of a network. The current in this branch is 2.2. A. If the resistance is increased to 7.5 Ω, the remaining circuit being the same, the current in this branch will be

2.2 A

less than 2.2 A

2.2 A or less than 2.2 A

2.2 A or less or more than 2.2 A

⇒ Which quantity controls the effectiveness of LED in emitting light?

Applied voltage

Current

Extent of doping

Temperature

⇒ For low impedance SAW filter the most suitable material for substrate of SAW filter is

PZT ceramics

ZnO

Lithium titanate

Lithium neobate

⇒ A volt ratio box should have low resistance.

TRUE

FALSE

⇒ One of the major applications of JFET is in

switching

constant current-source

constant voltage-source

electron flow regulation

⇒ Four inputs A, B, C, D are fed to a NOR gate. The output of NOR gate is fed to an inverter. The output of inverter is

A + B + C + D

A + B + C + D

ABCD

ABCD

⇒ Out of the three transforms viz. Z-transform, Laplace transform and Fourier transform

all three are used in continuous time domain

all three are used in both continuous time domain and discrete time domain

Z transform is used in continuous time domain while Laplace and Fourier transforms are used in discrete time domain

Z transform is used is discrete time domain while Laplace and Fourier transforms are used in continuous time domain

⇒ Which one is correct option?

Phase velocity is greater than light velocity

Group velocity is greater than light velocity

Phase velocity is equal to group velocity

Phase velocity is less than light velocity

⇒ The percentage saving in power when the carrier and one of the sidebands are suppressed in an AM wave modulated to a depth of 100% will be nearly

0.5

0.66

0.75

0.83

⇒ The Lissajous pattern observed on screen of CRO is a straight line inclined at 45° to x axis. If

*X*-plate input is 2 sin ω

*t*, the

*Y*-plate input is

2 sin ω

*t*

2 sin (ω

*t*+ 45°)

2 sin (ω

*t*- 45°)

22 sin ω

*t*+ 45°)

⇒

Match the following:

List I (Logic family) | List II (Characteristic) | ||
---|---|---|---|

A. | TTL | 1. | Maximum power consumption |

B. | ECL | 2. | Highest packing density |

C. | NMOS | 3. | Least power consumption |

D. | CMOS | 4. | Saturated Logic |

A-1, B-4, C-2, D-3

A-1, B-4, C-3, D-2

A-4, B-1, C-2, D-3

A-4, B-1, C-3, D-2

⇒ If the thermal resistance of a transistor is lower it means

higher junction temperature

lower junction temperature

higher or lower junction temperature depending on circuit conditions

higher or lower junction temperature depending on transistor

⇒ All network theorems of dc are applicable to ac also with different quantities taken as phasors.

TRUE

FALSE

⇒ When a normal atom loses an electron

the atom loses one-proton simultaneously

rest of the electrons move faster

the atom becomes a positive ion

the atom becomes a negative ion

⇒ When a line short circuited at far end, the minimum voltage occurs at

far end

source end

midway between source and far end

none of the above

⇒ Consider the following

- The first letter of a Java variable is lower case.
- Each successive word in Java variable begins with a capital letter.
- All other letters are lower case.
- A Java variable can have a digit as first character.

All

1, 2, 3 only

1, 2, 4 only

2, 3, 4 only

⇒ The types of carriers in a semiconductor are

1

2

3

4

⇒ In a lag network the input frequency is 100

*f*where

_{c}*f*is critical frequency. The voltage gain is

_{c}0 dB

-20 dB

-40 dB

-60 dB

⇒ For a npn BJT transistor

*f*is 1.64 x 10

_{β}^{8}H

*z*. C

_{μ}= 10

^{-14}F; C

_{p}= 4 x 10

^{-13}F and DC current gain is 90. Find

*f*and

_{T}*g*(

_{m}*f*= cut off frequency, C

_{β}_{μ}= capacitance, C

_{p}= parasitic capacitance,

*g*= transconductance,

_{m}*f*= gain BW product)

_{T}*f*= 1.47 x 10

_{T}^{10}H

*z*;

*g*= 38 milli mho

_{m}*f*= 1.64 x 10

_{T}^{8}H

*z*;

*g*= 30 milli mho

_{m}*f*= 1.47 x 10

_{T}^{9}H

*z*;

*g*= 38 mho

_{m}*f*= 1.33 x 10

_{T}^{12}H

*z*;

*g*= 0.37 m-mho

_{m}⇒ A frequency multiplier stage should operate as

class A

class AB

class C

either of the above

⇒ In sign magnitude numbers,

the leading bit stands for the sign

the leading bit is part of the magnitude

the leading bit is always 0

the leading bit is always 1