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Q1. | The generally used value of EHV supply in TV receivers is |

A. | 1 kV per diagonal cm [Wrong Answer] |

B. | 1 kV per diagonal inch [Correct Answer] |

C. | 0.5 kV per diagonal cm [Wrong Answer] |

D. | 0, 5 kV per diagonal inch [Wrong Answer] |

View Answer
Explanation:-
Answer : BDiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ The addition of impurity in extrinsic semiconductor is about 1 part in 10

^{8}parts.

TRUE

FALSE

⇒ A standard cell of 1.0185 V is used with a slide wire potentiometer. The balance was obtained at 60 cm. When an unknown emf was connected, the balance was obtained at 82 cm. The magnitude of unknown emf is

1.39 V

0.75 V

13.9 V

7.45 V

⇒ The converter whose conversion time is independent of number of bits is

dual stope

counter type

parallel conversion

successive approximation

⇒ Consider the z-transform X(

*z*) = 5

*z*

^{2}+ 4

*z*

^{-1}+ 3; 0 < |

*z*| < ∞ The inverse transform

*x*[

*n*] is

5δ[

*n*+ 2] + 3δ[

*n*] + 4δ[

*n*- 1]

5δ[

*n*- 2] + 3δ[

*n*] + 4δ[

*n*+ 1]

5

*u*[

*n*+ 2] + 3

*u*[

*n*] + 4

*u*[

*n*- 1]

5

*u*[

*n*- 2] + 3

*u*[

*n*] + 4

*u*[

*n*+ 1]

⇒ In the signal flow graph of the given figure, the number of forward path

1

2

3

4

⇒ In figure, the switch S is initially open and steady state conditions are reached. At

*t*= 0 switch is closed. The initial current through 2C capacito

zero

0.0416666666666667

0.0833333333333333

0.125

⇒ The two-transistor model of a thyristor consists of two transistors :

one

*n*-

*p*-

*n*and other

*p*-

*n*-

*p*

both

*p*-

*n*-

*p*

both

*n*-

*p*-

*n*

one

*n*-

*p*-

*n*and other UJT

⇒ Serial input data of 8085 can be loaded into bit-7 of the accumulator by

executing a RIM instruction

executing RSTI

using TRAP

none of the above

⇒ The input 3-dB frequency is :

100 Hz

148 Hz

100 kHz

None

⇒ Figure shows a pole zero plot of I(

*s*). The likely current response in time domai

*i*(

*t*) =

*e*

^{-1}-

*e*

^{-3t}

*i*(

*t*) =

*e*

^{-1}- 2

*e*

^{-2t}

*i*(

*t*) =

*e*

^{-1}-

*e*

^{-2t}

*i*(

*t*) =

*e*

^{-1}-

*e*

^{-4t}

⇒ As per BIS there are 6 accuracy classes of instruments.

TRUE

FALSE

⇒ In practical commercial AM system channel bandwidth is

150 kHz

100 kHz

15 kHz

200 kHz

⇒ For a plate-modulated class C amplifier the plate supply voltage is E. The maximum plate cathode voltage could be almost high as

2E

3E

4E

6E

⇒ The property is not valid for basic singularity function is

it is even signal

convolution of any arbitary function

*x*(

*t*) and an impulse is the original function itself

the sum of two impulses at same location is the impulse with the strength equal to the summation of individual strengths.

none of these.

⇒ A line is excited by a 100 V dc source. If reflection coefficients at both ends are 1 each then

there will be no oscillations on line

there will be only 1 or 2 oscillations on line

there will be a finite number of oscillations on line

the oscillations will continue indefinitely

⇒ The noise figure of individual stages of a two stage amplifier is 2.03 and 1.54 respectively. If gain of first stage is 62, the overall noise figure is

2.03

2.055

3.05

6.05

⇒ The output of basic DTL configuration is

low when one of the input is high

low when all inputs are high

high when all inputs are high

high when all inputs are low

⇒ Schering bridge operates at a high voltage of about 10 kV.

TRUE

FALSE

⇒ The radio horizon for space waves is about three-fourth as for as the optical horizon.

TRUE

FALSE

⇒ The inputs A, B, C of the given figure are applied to a 3 input NOR gate. The outpu

HIGH from 4 to 0

LOW from 0 to 4

HIGH from 0 to 1 and LOW from 1 to 4

LOW from 0 to 2 and HIGH from 2 to 4

⇒ In TE and TM modes of rectangular waveguides having propagation in

*z*direction

E

_{z}and H

_{z}are both zero

In TE mode E

_{z}is zero and in TM mode H

_{z}is zero

In TE mode H

_{z}is zero and in TM mode E

_{z}is zero

In both TE and TM modes both E

_{z}and H

_{z}are non-zero

⇒ A lens has a hyperfocal distance of 7.5 m. It is focused at 7.5 m. Then

all objects from 7.5 m to infinity will appear in focus

all objects from 3.75 m to infinity will appear in focus

all objects from 0 to 7.5 m will appear in focus

all objects from 0 to 3.75 m will appear in focus

⇒ An AM wave is given by

*s*(

*t*)

_{AM}= 20 (1 + 0.5 cos 10

^{3}

*t*+ 0.3 cos 10

^{4}

*t*cos 10

^{6}

*t*) the modulation index of the envelope is

0.5

0.58

0.3

0.8

⇒ The following circuit is implementation of:

- sum of full adder
- carry of half adder
- difference of full subtractor 1 only

3 only

2 only

1 and 2 both

⇒

Match the following:

List I (Operator) | List II (Description) | ||
---|---|---|---|

A. | ? : | 1. | Modulus |

B. | [ ] | 2. | Array expression |

C. | % | 3. | Conditional |

A-3, B-2, C-1

A-1, B-2, C-3

A-1, B-3, C-2

A-2, B-3, C-1

⇒ The graph of a network has 6 branches with 3 tree branches. The minimum number of equations required for solution of network is

2

3

4

5

⇒

**Assertion (A):** In AM, use of SSB reduces the power and bandwidth requirement

**Reason (R):** A balanced modulator produces AM with carrier suppressed

Both A and R are correct and R is correct explanation of A

Both A and R are correct but R is not correct explanation of A

A is correct but R is wrong

A is wrong but R is correct

⇒ Study the circuit of figure and examine the following statem

1, 2 and 3

1 and 2

1 and 3

2 and 3

⇒ The equation sin (

*z*) = 10 has

no real or complex solution

exactly two distinct complex solutions

a unique solution

an infinite number of complex solutions

⇒ A thermocouple instrument can be used over a very wide frequency range.

TRUE

FALSE