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The Ebers-moll equation for IE in CB configuration is given by | |
A. | IE = anICIEC0 [Wrong Answer] |
B. | IE = aIIC + IC0 [Wrong Answer] |
C. | IE = anIC + IC0(eqVEB/KT-1) [Wrong Answer] |
D. | IE = aIIC + IE0(eqVEB/KT - 1) [Correct Answer] |