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Q1. | The current i(t) through a 10 Ω resistor in series with an inductance is given by i(t) = 3 + 4 sin (100t + 45°) + 4 sin (300t + 60°) Amperes. The RMS value of the current and the power dissipated in the circuit are |

A. | 41 A, 410 W respectively [Wrong Answer] |

B. | 35 A, 350 W respectively [Wrong Answer] |

C. | 5 A, 250 W respectively [Correct Answer] |

D. | 11 A, 1210 W respectively [Wrong Answer] |

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