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Q1. | The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is ? |

A. | 5 : 2 [Wrong Answer] |

B. | 7 : 3 [Correct Answer] |

C. | 9 : 2 [Wrong Answer] |

D. | 13 : 4 [Wrong Answer] |

View Answer
Explanation:-
Answer : BDiscuss it below :Let the ages of father and son 10 years ago be 3x and x years respectively.Then, (3x + 10) + 10 = 2 [(x + 10) + 10] <=> 3x + 20 = 2x + 40 <=> x = 20. ∴ Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3. !! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

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