Question is ⇒ Pure aniline is evaporating through a stagnant air film of 1 mm thickness at 300 K and a total pressure of 100 KPa. The vapor pressure of aniline at 300 K is 0.1 KPa. The total molar concentration under these conditions is 40.1 mole/m3 . The diffusivity of aniline in air is 0.74xl0-5m2/s.The numerical value of mass transfer co-efficient is 7.4 x 10-3. Its units are, Options are ⇒ (A) m/s, (B) cm/s, (C) mole/m2.s.Pa, (D) kmole/m2.s.Pa, (E) , Leave your comments or Download question paper.

Question is ⇒ Pure aniline is evaporating through a stagnant air film of 1 mm thickness at 300 K and a total pressure of 100 KPa. The vapor pressure of aniline at 300 K is 0.1 KPa. The total molar concentration under these conditions is 40.1 mole/m3 . The diffusivity of aniline in air is 0.74xl0-5m2/s.The numerical value of mass transfer co-efficient is 7.4 x 10-3. Its units are, Options are ⇒ (A) m/s, (B) cm/s, (C) mole/m2.s.Pa, (D) kmole/m2.s.Pa, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	Pure aniline is evaporating through a stagnant air film of 1 mm thickness at 300 K and a total pressure of 100 KPa. The vapor pressure of aniline at 300 K is 0.1 KPa. The total molar concentration under these conditions is 40.1 mole/m³ . The diffusivity of aniline in air is 0.74xl0^-5m²/s.The numerical value of mass transfer co-efficient is 7.4 x 10^-3. Its units are
A.	m/s [Wrong Answer]
B.	cm/s [Wrong Answer]
C.	mole/m².s.Pa [Correct Answer]
D.	kmole/m².s.Pa [Wrong Answer]
View Answer 2 -5 Explanation:- Answer : C Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

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