Users Also Read

MCQ's Search Engine

Electrical Engineering

Mechanical Engineering

Civil Engineering

Automobile Engineering

Chemical Engineering

Computer Engineering

Electronics Engineering

Medical Science Engg

Q1. | Match the following:
| ||||||||||||||||||||

A. | A-2, B-3, C-4, D-1 [Correct Answer] | ||||||||||||||||||||

B. | A-1, B-3, C-4, D-2 [Wrong Answer] | ||||||||||||||||||||

C. | A-2, B-4, C-3, D-1 [Wrong Answer] | ||||||||||||||||||||

D. | A-1, B-4, C-3, D-2 [Wrong Answer] | ||||||||||||||||||||

View Answer
Explanation:-
Answer : ADiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ In the circuit shown, the device connected to Y5 can have address in the r

2000 - 20FF

2D00 - 2DFF

2E00 - 2EFF

FD00 - FDFF

⇒ Three capacitors each 9 μF are connected in delta. The value of each capacitor in equivalent star connection is

3 μF

6 μF

27 μF

81 μF

⇒ Which op-amp circuit uses a diode as one of the circuit components?

Integrating amplifier

Differentiating amplifier

Logarithmic amplifier

Summing amplifier

⇒ If B = 4 +

*j*3, (B)

^{1/3}=

2 ∠30°

2 ∠36.87°

1.71 ∠12.3°

1.71 ∠30°

⇒ If

*p*is the probability of success and

*q*is the probability of failure, then the probability that there are

*r*successes in

*n*trails is

^{n}

*c*

_{r}

*p*

^{r}*q*

^{n}

^{-}

^{r}

^{n}*c*

_{r}

*p*

^{n -}

^{r}*q*

^{r}^{n}

*c*

_{r}

*p*

^{r}*q*

^{n}

^{+}

^{r}

^{n}*c*

_{r}*p*

^{n}*q*

^{n}^{- r}

⇒ The satellites used for intercontinental communication are called

Comsat

Domsat

Marisat

Intelsat

⇒ Values of V

_{T}at 20°C for an ideal P-N diode

25.27 mV

30.3 mV

23 mV

50 mV

⇒ The gain margin for a stable system

has a positive decibel value

has a negative decibel value

has a large negative decibel value

none of the above

⇒ A linear displacement digital transducer generally uses

straight binary code

BCD

gray code

hexadecimal code

⇒ The hexadecimal number 5 F is equal to binary number

1010011

1011001

1010101

1011111

⇒ The number of LED display indicators in logic probe are

1

2

1 or 2

4

⇒ When measuring phase angle between two waves using a CRO, the time base generator is connected to

X plate

Y plate

both X and Y plate

neither X nor Y plates

⇒ For a npn BJT transistor

*f*is 1.64 x 10

_{β}^{8}H

*z*. C

_{μ}= 10

^{-14}F; C

_{p}= 4 x 10

^{-13}F and DC current gain is 90. Find

*f*and

_{T}*g*(

_{m}*f*= cut off frequency, C

_{β}_{μ}= capacitance, C

_{p}= parasitic capacitance,

*g*= transconductance,

_{m}*f*= gain BW product)

_{T}*f*= 1.47 x 10

_{T}^{10}H

*z*;

*g*= 38 milli mho

_{m}*f*= 1.64 x 10

_{T}^{8}H

*z*;

*g*= 30 milli mho

_{m}*f*= 1.47 x 10

_{T}^{9}H

*z*;

*g*= 38 mho

_{m}*f*= 1.33 x 10

_{T}^{12}H

*z*;

*g*= 0.37 m-mho

_{m}⇒ McMurray Bedford full bridge inverter uses

natural commutation

auxiliary commutation

complementary commutation

any of the above

⇒ In figure, the effective capacitance between A and

2 μF

4 μF

8 μF

10 μF

⇒ The frequencies in ultra high frequency range are propagated by means of __________ waves

surface

ground

sky

space

⇒ A 2 bit binary multiplier can be implemented using

2 I/P only

2 I/P XOR

*and 4 I/P and gates only*

_{s}two 2 I/P

_{s}NOR and one XNOR gate

XOR gates and shift Register

⇒ Consider the following reasons for using antenna coupler

- To prevent illegal radiation of spurious frequencies
- To tune out reactive components of antenna impedance
- To have correct value of load impedance for transmitter.

1, 2, 3

1, 2

1 only

2, 3

⇒ A steel bar needs 1200 AT to magnetise it. The voltage that must be applied to the magnetising coil of 100 turns and 10 Ω resistance is __________ volt.

120

12

1200

10

⇒ In a bipolar junction transistor a

_{dc}= 0.98, I

_{CO}= 2 μA and 1

_{B}= 15 μA. The collector current I

_{C}is

635 mA

735 mA

835 mA

935 mA

⇒ If noise margin is high, there is lesser chance of false operation.

TRUE

FALSE

⇒ If 1.5% of the output of an amplifier is feedback positively to the input, the minimum gain required of the amplifier for oscillations to occur, is

16.6

44.4

66.6

75

⇒

**Assertion (A):** The 'do while' statement is used less frequently than the 'while' statement.

**Reason (R):** For most applications it is more natural to test for continuation of loop at the beginning than at the end of loop.

Both A and R are correct and R is correct explanation of A

Both A and R are correct but R is not correct explanation of A

A is correct R is wrong

A is wrong R is correct

⇒ Consider the following network func

zero at origin

zero at infinity

pole at origin

pole at infinity

⇒ A magnetic circuit has an iron length of 20 cm and air gap length 0.1 cm. If μ

_{r}= 200 then

mmf for iron and air gap are equal

mmf for iron is much less than that for air gap

mmf for iron is much more than that for air gap

either (a) or (c)

⇒ The resolution of 4 bit counting ADC is 0.5 volt, for an Analog input of 6.6 volts. The digital output of ADC will be

1011

1101

1100

1110

⇒ The circuit of figure is used to measure the value R

_{x}. Ammeter resistance R

_{a}= 0.1 Ω voltmeter resistance R

_{v}= 5000 Ω. It R

_{x1}and R

_{x2}, are the measured values of R

_{x}with switch in position 1 and 2, the mean of R

_{x1}, and R

_{x2},

9.98 Ω

10 Ω

10.04 Ω

10.1 Ω

⇒ In figure, which value of Z

_{L}will cause maximum power to be transferred to the l

2 +

*j*2 Ω

2 -

*j*2 Ω

- 2 Ω

2 Ω

⇒ The

*r*

_{e}model equivalent circuit shown in figure is

CE amplifier

CC amplifier

CB amplifier

None of the above

⇒ Two meters X and Y require 40 mA and 50 mA for full scale deflection. Then

X is more sensitive

Y is more sensitive

both are equally sensitive

it is not possible to determine from given data