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Q1. | Match the following:
| ||||||||||||||||||||

A. | A-1, B-2, C-3, D-4 [Wrong Answer] | ||||||||||||||||||||

B. | A-4, B-3, C-2, D-1 [Correct Answer] | ||||||||||||||||||||

C. | A-2, B-4, C-1, D-3 [Wrong Answer] | ||||||||||||||||||||

D. | A-3, B-1, C-4, D-2 [Wrong Answer] | ||||||||||||||||||||

View Answer
Explanation:-
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**Also Read Similar Questions Below :**

⇒ Thermal noise has a power spectral density which is quite uniform upto frequencies in the order of

100 Hz

10

^{6}Hz

10

^{9}Hz

10

^{13}Hz

⇒ Good frequency stability can be available

crystal oscillators

Hartley oscillators

colpitts oscillators

none of the above

⇒ No load d.c. output will be least in case of

half wave rectifier

full wave rectifier

bridge rectifier

three phase full wave rectifier

⇒ A voltage wave having 5% fifth harmonic content is applied to a series RC circuit. The percentage fifth harmonic content in the current wave will be

0.05

more than 5%

less than 5%

equal or more than 5%

⇒ A moving coil meter has a resistance of 50 ohms and a full scale deflection current of 20 mA. To convert it into a voltmeter of 0-100 V range, the series resistance should be

5000 Ω

5050 Ω

4950 Ω

505 Ω

⇒ In two wattmeter method of 3 phase power measurement, when does one wattmeter read negative

when power factor is less than 0.5 lagging

when power factor is greater than 0.5 lagging

when power factor is less than 0.5

when power factor is unity

⇒ To plot frequency spectrum we draw two graphs

*viz*|F

*| versus frequency and φ*

_{n}*versus frequency.*

_{n}TRUE

FALSE

⇒ The relaxation time of electrons in a metal is of the order of

10

^{-6}secs

10

^{-10}secs

10

^{-14}secs

10

^{-20}secs

⇒ Bitter powder patterns prove the existence of domains.

TRUE

FALSE

⇒ A TEM wave is incident normally on a perfect conductor. The E and H fields at boundary will respectively be

minimum and maximum

minimum and minimum

maximum and minimum

maximum and maximum

⇒ Which of the following is very useful as multiband HF receiving antenna?

Square loop

Conical horn

Folded dipole

Log-periodic

⇒ The divergence of a vector is a scalar, while the curl of a vector is another

scalar

vector

unit vector

none of the above

⇒

Match the following:

List I | List II | ||
---|---|---|---|

A. | Ring modulator | 1. | Clock recovery |

B. | VCO | 2. | Demodulation of FM |

C. | Foster Seeley discriminator | 3. | Frequency conversion |

D. | Mixer | 4. | Summing of two points |

5. | Generation of FM | ||

6. | Generation of DSB-SC |

A-1, B-3, C-2, D-4

A-6, B-5, C-2, D-3

A-6, B-1, C-3, D-2

A-5, B-6, C-1, D-3

⇒ Poynting vector is associated with

flux in magnetic field

power flow in electrostatic field

current in electrostatic field

charge in electrostatic field

⇒ What is the purpose of using ALE signal high?

To latch low order address from bus to separate A

_{0}- A

_{7}lines

To latch data D

_{0}- D

_{7}from bus to separate data bus

To disable data bus latch

All of the above

⇒ Load cell uses

piezoelectric crystal

capacitor

mutual inductance

strain gauge

⇒

**Assertion (A):** Inverse Laplace transform can be found from P(*s*) by inversion integral.

**Reason (R):** The function f(*t*) is assumed to be zero for *t* < 0.

Both A and R are correct and R is correct explanation of A

Both A and R are correct but R is not correct explanation of A

A is correct but R is wrong

R is correct but A is wrong

⇒ A constant

*k*low pass filter has

*f*

_{c}= 500 Hz. At

*f*= 1000 Hz, the attenuation is

zero

infinity

may be zero or infinity

more than zero but less than infinity

⇒

Match the following:

List I | List II | ||
---|---|---|---|

A. | Zener diode | 1. | used in seven segment display |

B. | Tunnel diode | 2. | used in voltage regulator circuits |

C. | LED | 3. | used is solar energy utilization |

D. | Photovoltaic cell | 4. | used in digital circuits |

A-1, B-3, C-2, D-4

A-2, B-3, C-1, D-4

A-2, B-4, C-1, D-3

A-3, B-2, C-4, D-1

⇒ In a broadcast superheterodynes receiver having no RF amplifier, the loaded Q of the antenna coupling circuit is 100. If the intermediate frequency is 455 kHz. The image frequency at 25 MHz will be

24.09 MHz

24.54 MHz

25.45 MHz

25.91 MHz

⇒ An n type semiconductor is illuminated by a steady flux of photons with energy greater than the band gap energy. The change in conductivity Δσ obeys which relati

Δσ = 0

Δσ =

*e*(σ

_{n}+ σ

_{p}) Δ

_{n}

Δσ =

*e*(μ

_{n}Δ

_{n}- μ

_{p}Δ

_{p})

Δσ =

*e*μ

_{n}Δ

_{n}

⇒ In a CE amplifier, the collector resistance is 6 kΩ and load resistance is 3 kΩ. The ac load resistance is

9 kΩ

6 kΩ

3 kΩ

2 kΩ

⇒ Kelvin's double bridge is used to measure low resistances because

it has high sensitivity

there is no thermoelectric emf

resistance variation due to temperature

effect of contact and lead resistances is eliminated

⇒ A voltage v = 5 + 50 sin ω

*t*/ + 5 sin 5 &omega

*t*is applied to a pure capacitor of capacitance 1 ωF. If

*f*/= 314 rad/sec, current is

1 + 0.0157 cos 314

*t*+ 0.00785 cos 1570

*t*

0.0157 cos 314

*t*+ 0.00785 cos 1570 t

0.0157 sin 314

*t*+ 0.00785 sin 1570

*t*

0.0157 sin (314

*t*/ + 45°) + 0.00785 sin (1570

*t*+ 45°)

⇒ If X(

*z*) = 2

*az*

^{-1}/(1 -

*az*

^{-1})

^{3}and |

*a*| < |

*z*|, then the initial value

*x*

_{0}is

0

1

∞

2

⇒ The main disadvantage of a JFET is

low gain-bandwidth product

high noise level

high cost

low gain

⇒ In figure, the short circuit current through terminal AB wil

1.5 A

0.125

0.0833333333333333

0.0416666666666667

⇒ In figure the output

*v*(

*t*)

an amplitude modulated signal

a frequency modulated signal

a phase modulated signal

none of the above

⇒ If sound wave has an intensity of 10 Pa. The dB level is about

1.139 dB

11.39 dB

113.9 dB

1139 dB

⇒ The value of VSWR is taken as ∞ when the line is

short-circuited

open-circuited

terminated with full load

terminated with load equal to the characteristic impedance of the load