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Q1. | Match the following:
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A. | A-2, B-3, C-4 [Wrong Answer] | ||||||||||||||||||||||||

B. | A-4, B-3, C-2 [Correct Answer] | ||||||||||||||||||||||||

C. | A-5, B-4, C-3 [Wrong Answer] | ||||||||||||||||||||||||

D. | A-1, B-2, C-5 [Wrong Answer] | ||||||||||||||||||||||||

View Answer
Explanation:-
Answer : BDiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ Decimal 1932 when converted into 10's complement will become

8868

8060

8608

8806

⇒ The condition AD - BC = 1 for two port network implies that the network is a

reciprocal

lumped element network

lossless network

unilateral element network

⇒ A telephone channel requires a bandwidth of about

1 kHz

3 kHz

10 kHz

50 kHz

⇒ DMA stands for

Direct Memory Address

Distributed Memory Address

Direct Memory Accumulator

Decimal Machine Address

⇒ The common-drain amplifier, better known as the source follower, has a voltage gain __________ and the output signal is __________ with the input signal.

approaching unity, in phase

approaching unity, out of phase

is very high, in phase

is very high, in reverse phase

⇒ A 120 V, 30 Hz source feeds a half wave rectifier circuit through a 4 : 1 step down transformer, the average output voltage is

30 V

13.5 V

10 V

7.07 V

⇒ Find the value of K and velocity constant K

*so that the maximum overshoot in the unit step response is 0.2 and the peak time is 1*

_{v}12.37, 0.175

12.86, 2.175

11.36, 1.175

1.86, 0.175

⇒ An ac network has two sources of the same frequency. The currents in one branch when the sources act independently are 10 ∠30° A and 10 ∠60° A. When both sources act, the current in the branch should be

19.32 ∠45°

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⇒ At very low temperatures, semiconducting materials behave as insulators.

TRUE

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⇒ Which of the following circuit does not need a coupling capacitor?

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⇒ Narrow band FM signal can be represented as

A cos (2p

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_{c}t*A*sin (2p

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_{m}tA cos (2p

*f*) - β

_{m}t*A*sin (2p

*f*) sin (2p

_{c}t*f*)

_{m}tA cos (2p

*f*) + β

_{c}t*A*sin (2p

*f*) sin (2p

_{c}t*f*)

_{m}tA cos (2p

*f*) + β

_{m}t*A*sin (2p

*f*) sin (2p

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Match the following:

List I | List II | ||
---|---|---|---|

A. | True type | 1. | Type of calculator in window |

B. | FIND | 2. | Window command |

C. | WORD PAD | 3. | Name of a Font |

D. | STANDARD | 4. | Has many features of a simple word processor |

A-1, B-2, C-3, D-4

A-4, B-3, C-2, D-1

A-3, B-2, C-1, D-4

A-3, B-2, C-4, D-1

⇒ Find V

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⇒ In a system using QASK and 4 bits to form a symbol, the required bandwidth is

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half of that in BPSK

one-fourth of that in BPSK

none of the above

⇒ Fourier transform is defined for

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1100

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**Assertion (A):** In *p* type semiconductor conduction is mainly due to holes.

**Reason (R):** In *p* type material the holes are majority carriers.

Both A and R are true and R is correct explanation of A

Both A and R are true but R is not a correct explanation of A

A is true but R is false

A is false but R is true

⇒ A rectangular waveguide (2.29 x 1.02) cm operates at a freq. of 11 GHz in TE

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31.11 W

31.11 kW

31.11 MW

⇒

**Assertion (A):** If power gain doubles the power gain increases by 3 dB

**Reason (R):** The bel power gain of cascaded stages is equal to sum of each bel power gain

Both A and R are correct and R is correct explanation for A

Both A and R are correct but R is not correct explanation for A

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A is wrong R is correct

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lies in left half plane

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⇒ Large scale integration refers to

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⇒ According to maximum power transfer theorem, if the load is inductive, the source should be

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any of the above