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Assertion (A): In an R-L circuit having high inductance, the rise of current is very slow. Reason (R): The time constant of R-L circuit is L/R. | |
A. | Both A and R are true and R is correct explanation of A [Correct Answer] |
B. | Both A and R are true and R is not the correct explanation of A [Wrong Answer] |
C. | A is true but R is false [Wrong Answer] |
D. | A is false but R is true [Wrong Answer] |
View Answer
Explanation:-
Answer : A Discuss it below : !! OOPS Login [Click here] is required to post your answer/result |
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14 Ω
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X plates
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has low input resistance
has high gate current
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is always equal to ac signal voltage
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is always less than ac signal voltage
may be equal or more or less than ac signal voltage
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increasing the length of wire
decreasing the length of wire
increasing the current in the wire
decreasing the current in the wire
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-256
-128
-255
-127
⇒ A rectangular waveguide measures 3 x 4.5 cm internally and has a 10 GHz signal propagated in it. Calculate the cut off frequency for dominant mode.
4 GHz
7.5 GHz
5 GHz
10 GHz
⇒ In figure the phase
will be 90° at ω = 0 and 0° at ω = ∞
will be 0° at ω = 0 and 90° at ω = ∞
will be 45° at ω = 0 and 0° at ω = ∞
will be 45° at ω = 0 and 90° at ω = ∞
⇒ When P_{c} is the unmodulated carrier power and P_{t} is the total power in the modulated wave, then the maximum power in AM wave is
P_{t} = 1.5 P_{c}
P_{t} = 2.5 P_{c}
P_{t} = 2
P_{t} = 22 P_{c}
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undamped
over damped
under damped
critically damped
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Clapp oscillator
R-C Phase shift oscillator
Hartley oscillator
Colpitt's oscillator
⇒ Three analog signals, having bandwidths 1200 Hz, 600 Hz, 600 Hz are sampled at their Nyquist rates, encoded with 12 bit words, and time division multiplexed. The bit rate for the multiplexed signal is
115.2 kbps
28.8 kbps
57.6 kbps
38.4 kbps
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z_{11} = z_{22}
z_{12} = z_{21}
z_{11} z_{22} and z_{12} = z_{21}
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0
0.208333333333333
less than 5A
infinity