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Assertion (A): C allows the use of logical operators, AND, OR, NOT. Reason (R): C has logical operators as well as bitwise operators like AND, OR etc. | |
A. | Both A and R are correct and R is correct explanation of A [Wrong Answer] |
B. | Both A and R are correct but R is not correct explanation of A [Correct Answer] |
C. | A is correct R is wrong [Wrong Answer] |
D. | A is wrong R is correct [Wrong Answer] |
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Explanation:-
Answer : B Discuss it below : !! OOPS Login [Click here] is required to post your answer/result |
Also Read Similar Questions Below :
⇒ If the peak value of output of a half wave rectifier is 100 V, the rms value is
100 V
50 V
70.7 V
35.35 V
⇒ The addition of p type impurity to intrinsic material creates allowable energy levels.
slightly below conduction band
slightly above conduction band
slightly below valence band
slightly above valence band
⇒ The V_{o} of the op-amp circuit shown in the give
11 V_{i}
10 V_{i}
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zero
⇒ 7483 is a TTL binary adder. It can add
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four 6-bit binary numbers
four 8-bit binary numbers
any number of 4-bit numbers
⇒ In the circuit, V_{s} = 10 cos ωt, power drawn by the 4Ω resistor is 8 watt. The power facto
1
0.5
0.85
0
⇒ A transistor with a = 0.98 then β will be
49
50
47
48
⇒ Which one of the following pairs is not correctly matched?
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Gd : Paramagnetic
Ferrite : Ferrimagnetic
Cr_{2} O_{3} : Ferromagnetic
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A-1, B-2, C-3, D-4
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⇒ In brushless excitation system of modern alternators, the main exciter is
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⇒ Fourier series is applicable for
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⇒ A longwave AM broadcast transmitter needs
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⇒ If the peak value of output of a half wave rectifier is 100 V, the rms value is
100 V
50 V
70.7 V
35.35 V
⇒ The addition of p type impurity to intrinsic material creates allowable energy levels.
slightly below conduction band
slightly above conduction band
slightly below valence band
slightly above valence band
⇒ The V_{o} of the op-amp circuit shown in the give
11 V_{i}
10 V_{i}
V_{i}
zero
⇒ 7483 is a TTL binary adder. It can add
two 4-bit binary numbers
four 6-bit binary numbers
four 8-bit binary numbers
any number of 4-bit numbers
⇒ In the circuit, V_{s} = 10 cos ωt, power drawn by the 4Ω resistor is 8 watt. The power facto
1
0.5
0.85
0
⇒ A transistor with a = 0.98 then β will be
49
50
47
48
⇒ Which one of the following pairs is not correctly matched?
NaCl : Diamagnetic
Gd : Paramagnetic
Ferrite : Ferrimagnetic
Cr_{2} O_{3} : Ferromagnetic
⇒ Foster Seeley discriminator uses a
single tuned circuit
double tuned circuit with primary and secondary tuned to the same frequency
double tuned circuit with primary and secondary tuned to the different frequency
none of the above
⇒
Match the following:
List I | List II | ||
---|---|---|---|
A. | RF amplifier | 1. | Amplifier received carrier and sidebands |
B. | Loudspeaker | 2. | Gives acoustic output |
C. | Demodulator | 3. | Has IF input and AF output |
D. | IF amplifier | 4. | Fixed-tuned to intermediate frequency |
A-1, B-2, C-3, D-4
A-2, B-1, C-3, D-4
A-3, B-4, C-1, D-2
A-1, B-4, C-3, D-2
⇒ Which materials find application in MASER?
Diamagnetic
Paramagnetic
Ferromagnetic
Ferrimagnetic
⇒ A string constant in basic is
a string of capital alphabets A to Z, included in question mark
a string of capital alphabets A to Z and digits 0 to 9 included in question mark
a string of capital alphabets A to Z, digits 0 to 9 and special characters
a string of capital alphabets A to Z, digits 0 to 9 and special characters included in question mark
⇒ Which control action is also called rate control?
Proportional
Derivative
Integral
Proportional plus integral
⇒ Which of the following is not necessarily the advantages of a push pull amplifier?
It gives more output
It removes odd a well as even harmonics
There is no effect of ripple of the power supply
It consumes least power
⇒ In a second order undamped system, the poles are on
positive real axis
imaginary axis
negative real axis
either (a) or (c)
⇒ If V_{a1}, V_{a2}, V_{a0} are the symmetrical components of V_{a}, then
V_{a} = V_{a1} + V_{a2} + V_{a0}
V_{a} = a^{2}V_{a1} + aV_{a2} + V_{a0}
V_{a} = aV_{a1} + a^{2}V_{a2} + V_{a0}
V_{a} = aV_{a0} + a^{2}V_{a1} + V_{a2}
⇒ In brushless excitation system of modern alternators, the main exciter is
dc generator
ac generator
either dc or ac generator
induction generator
⇒ A Ge diode operated at a junction temperature of 27°C. For a forward current of 10 mA, V_{D} is found to be 0.3 V. If V_{D} = 0.4 V then forward current will be
400 mA
475 mA
477 mA
480 mA
⇒
Assertion (A): The sign and magnitude of displacement can be measured by an LVDT.
Reason (R): LVDT is based on the principle of mutual inductance.
Both A and R are true and R is correct explanation of A
Both A and R are true but R is not correct explanation of A
A is true R is false
A is false R is true
⇒ The voltage across the secondary of the transformer in a half wave rectifier with a shunt capacitor filter is 50 volts. The maximum voltage that will occur on the reverse biased diode will be
100 V
88 V
50 V
25 V
⇒ Broadcasting antennas are generally
omnidirectional type
vertical type
horizontal type
helical
⇒ The presence of some holes in an intrinsic semiconductor at room temperature is due to
valence electrons
doping
free electrons
thermal energy
⇒ The dimensions of EMF are
ML^{2}I^{-1}T^{-3}
M^{-1}T^{-3}
ML^{2}I^{-2}T^{-3}
ML^{3}I^{-1}T^{-3}
⇒ In an ac circuit the fundamental component of current wave lags the corresponding voltage wave by 20°. The third harmonic component of current wave lags the corresponding voltage by an angle.
less than 20°
more than 20°
equal to 20°
equal to or more than 20°
⇒ In a bipolar transistor, the emitter base junction has
forward bias
reverse bias
zero bias
zero or reverse bias
⇒ Bode magnitude plot is drawn between
magnitude of network function and ω
dB magnitude and log ω
dB magnitude and ω
log_{e} (magnitude) and log ω
⇒ A moving coil instrument has a resistance of 0.6 Ω and full scale deflection at 0.1 A. To convert it into an ammeter of 0-15 A range, the resistance of shunt should be
0.6 Ω
0.06 Ω
0.1 Ω
0.004 Ω
⇒ Fourier series is applicable for
periodic
finite duration
non periodic
a and b
⇒ A longwave AM broadcast transmitter needs
very small carrier power
very large carrier power
small carrier power
large carrier power
⇒ A broadside array consisting of 200 cm wavelength with 10 half-wave dipole spacing 10 cm. And if each array element feeding with 1 amp. current and operating at same frequency then find the radiated power
730 W
73 W
100 W
None
⇒ A transmitter power of 5 W is increased by 20 dB. The effective radiated power is
5 W
100 W
25 W
500 W