Question is ⇒ <ol style="list-style-type: decimal; padding-bottom:10px;"><li style="padding-top:10px;">P(s) = s4 + s3 + 2s2 + 4s + 3</li><li style="padding-top:10px;">Q(s) = s4 + 2s3 + s</li></ol> Which one of the following statements in correct for above P(s) and Q(s) polynomials?, Options are ⇒ (A) Both P(s) and Q(s) are Hurwitz, (B) Both P(s) and Q(s) are non-Hurwitz, (C) P(s) is Hurwitz but Q(s) is non-Hurwitz, (D) P(s) is non-Hurwitz but Q(s) is Hurwitz, (E) , Leave your comments or Download question paper.

Question is ⇒ <ol style="list-style-type: decimal; padding-bottom:10px;"><li style="padding-top:10px;">P(s) = s4 + s3 + 2s2 + 4s + 3</li><li style="padding-top:10px;">Q(s) = s4 + 2s3 + s</li></ol> Which one of the following statements in correct for above P(s) and Q(s) polynomials?, Options are ⇒ (A) Both P(s) and Q(s) are Hurwitz, (B) Both P(s) and Q(s) are non-Hurwitz, (C) P(s) is Hurwitz but Q(s) is non-Hurwitz, (D) P(s) is non-Hurwitz but Q(s) is Hurwitz, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	P(s) = s⁴ + s³ + 2s² + 4s + 3 Q(s) = s⁴ + 2s³ + s Which one of the following statements in correct for above P(s) and Q(s) polynomials?
A.	Both P(s) and Q(s) are Hurwitz [Wrong Answer]
B.	Both P(s) and Q(s) are non-Hurwitz [Wrong Answer]
C.	P(s) is Hurwitz but Q(s) is non-Hurwitz [Correct Answer]
D.	P(s) is non-Hurwitz but Q(s) is Hurwitz [Wrong Answer]
View Answer 1 -1 Explanation:- Answer : C Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

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