Question is ⇒ Minute cracks in metals and minute faults in welded joints can be detected using, Options are ⇒ (A) IR rays, (B) UV rays, (C) <span class="symbol">a</span> rays, (D) X-ray/γ-rays, (E) , Leave your comments or Download question paper.

Question is ⇒ Minute cracks in metals and minute faults in welded joints can be detected using, Options are ⇒ (A) IR rays, (B) UV rays, (C) <span class="symbol">a</span> rays, (D) X-ray/γ-rays, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	Minute cracks in metals and minute faults in welded joints can be detected using
A.	IR rays [Wrong Answer]
B.	UV rays [Wrong Answer]
C.	a rays [Wrong Answer]
D.	X-ray/γ-rays [Correct Answer]
View Answer 1 -1 Explanation:- Answer : D Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

Previous question Next question

Also Read Similar Questions Below :

⇒ In the circuit, shown in figure, V₀ = V_i. The values of 1, m, n are: (x represents don't care conditi
0, 1, 1
∞, x, x
x, ∞, x
0, x, ∞

⇒ PAM stands for
Pulse Analogue Modulation
Phase Analogue Modulation
Pulse Amplitude Modulation
Phase Amplitude Modulation

⇒ Magnesium is alloyed with conducting materials for antenna primarily with the purpose of
increasing efficiency
improving radiative power
reducing weight
increasing density

⇒ In the circuit of figure, the value of r_e is (neglecting v_{be100 Ω
75 Ω
50 Ω
25 Ω}

⇒ Short circuit is the dual of open circuit.
TRUE
FALSE

⇒ Inverter 74 LS04 has following specifications I_0H max = - 0.4 mA, I_{0L max} = 8 mA, I_{IH max} = 20 μA, I_{IL max} = 0.
10
20
60
100

⇒

Assertion (A): The resolution of a DAC depends on the number of bits

Reason (R): Low resolution leads to fine control.

Both A and R are correct and R is correct explanation of A
Both A and R are correct but R is not correct explanation of A
A is true, R is false
A is false, R is true

⇒ If load impedance Z_L >> Z₀, then
Z₀ = Z_L (VSWR)
Z_L = Z₀ (VSWR)
Z_L = Z₀ (VSWR - 1)
Z_L = Z₀ VSWR

⇒ Hall effect is observed in a specimen when it is carrying current and is placed in a magnetic field. The resultant electric field inside the specimen is
normal to both current and magnetic field
in the direction of current
antiparallel to magnetic field
in arbitrary direction

⇒ In an homogeneous dielectric subjected to an electric field E, the dipole moment per unit volume is ∈₀(∈_r - 1) E.
TRUE
FALSE

⇒ The input impedance of short-circuited line of length l where l < λ/4
inductive
capacitive
resistive
none of the above

⇒ A voltmeter using thermocouples measures
rms value
peak value
average value
peak to peak value

⇒

Match the following:

	List I		List II
A.	Horn antenna	1.	High directivity
B.	Parabolic antenna	2.	Very high directivity
C.	Lens antenna	3.	Moderate directivity

A-1, B-2, C-3
A-3, B-2, C-1
A-3, B-1, C-2
A-1, B-3, C-2

⇒ In the analysis of common emitter amplifier we may neglect
h_re
h_oe
h_fe
h_ie

⇒ A silicon PN junction diode under reverse bias has depletion region of width 10 μm. The relative permittivity of silicon, ε_r = 11.7 and the permittivity of free space ε₀ = 8.85 x 10^-12 F/m. The depletion capacitance of the diode per square meter is
100 μF
10 μF
1 μF
20 μF

⇒ A transistor in CE mode is in saturation region. Then the collector is almost at
ground potential
a potential equal to V_CC
a potential equal to 0.5 V_CC
a potential equal to 2 V_CC

⇒ A-P type material has an acceptor ion concentration of 1 x 10¹⁶ per cm³. Its intrinsic carrier concentration is 1.48 x 10¹⁰/ cm. The hole and electron mobilities are 0.05m²/V-sec and 0.13 m²/V-sec respectively calculate the resistivity of the material
12.5 Ω-cm
1.25 Ω-cm
0.125 Ω-cm
125 Ω-cm

⇒ Conductivity σ, mobility μ and Hall coefficient K_H are related as
μ = σK_H
σ = μK_H
K_H = μσ
K_H =(μσ)^1.1

⇒ The system with given pole-zero diagra
casual
non-casual
both sided
not-possible

⇒ The different channels in a TDM receiver are separated by
integration
differentiation
AND gate
OR gate

⇒ In a J-K flip flop the input J = K = 1 pulse is about
set
reset
no change
toggle

⇒ The open loop gain of an ideal op-amp is
infinite
very high
neither high nor low
low

⇒ Schering bridge is used to measure
capacitance and dielectric loss
inductance
resistance
mutual inductance

⇒ A pre-emphasis circuit
boosts base frequencies
pre amplifies the complete audio band
amplifies higher audio frequencies
converts FM into phase modulation

⇒ The carriers of n channel JFET are
free electrons and holes
holes
free electrons or holes
free electrons

⇒ Which of the following is a valid real constant in FORTRAN 77?
1.2 E 231
3 E - 2
-3.2 E 2.3
1.2 E 23

⇒ The impulse response h[n] of a linear time invariant system is give
42 e^jpn/4
42 e^{- jpn/4}
4e^pn/4
-4e^pn/4

⇒ The ASCII code is
5-bit code
7-bit code
9-bit code
11-bit code

⇒ Which of the following values represents the open loop gain of typical op-amp?
100
10000
100000
1000000

⇒ The characteristic impedance of loss less transmission line is
L/R
L/C
1/LC
C/L