Question is ⇒ Low frequency boost can be easily compensated by, Options are ⇒ (A) attenuating the frequencies from 0 to 1.25 MHz, (B) using an appropriate de-emphasis circuit in the receiver, (C) using an appropriate pre-emphasis circuit in the transmitter, (D) none, (E) , Leave your comments or Download question paper.

Question is ⇒ Low frequency boost can be easily compensated by, Options are ⇒ (A) attenuating the frequencies from 0 to 1.25 MHz, (B) using an appropriate de-emphasis circuit in the receiver, (C) using an appropriate pre-emphasis circuit in the transmitter, (D) none, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	Low frequency boost can be easily compensated by
A.	attenuating the frequencies from 0 to 1.25 MHz [Correct Answer]
B.	using an appropriate de-emphasis circuit in the receiver [Wrong Answer]
C.	using an appropriate pre-emphasis circuit in the transmitter [Wrong Answer]
D.	none [Wrong Answer]
View Answer 1 -1 Explanation:- Answer : A Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

Previous question Next question

Also Read Similar Questions Below :

⇒ The analog signal given below is sampled at 1200 samples per second. m(t) = 2 sin 120 pt + 3 sin 240 pt + 4 sin 360 pt + 5 sin 480 pt + 6 sin 600 pt + 7 sin 720 pt. The folding (maximum) frequency is __________ .
300 Hz
360 Hz
600 Hz
480 Hz

⇒ If f(t) = r (t - a), F(s) =
e^-as/s²
a/(s + a)
1/(s + a)
e^-as/s

⇒ The factor η for a UJT is about
0.1
0.2
0.6
0.9

⇒ The dynamic resistance of a forward biased p-n diode
varies inversely with current
varies directly with current
is constant
is either constant or varies directly with current

⇒ There are four different algorithms A1, A2, A3 and A4 to solve, a given problem with the complexity order log(n), log(log(n)), n log and n/log(n) respectively. Which is the best algorithm?
A1
A2
A3
A4

⇒ Resistivity of copper is nearly
1.56 μ ohm-cm
3.95 μ ohm-cm
14.55 μ ohm-cm
22.05 μ ohm-cm

⇒

Assertion (A): The Fourier series of the wave shown in the figure does not contain even harmao
Both A and R are correct and R is correct explanation of A
Both A and R are correct but R is not correct explanation of A
A is true, R is false
A is false, R is true

⇒ Consider the following stateme
1 and 2
2 and 3
3 and 4
4 and 5

⇒ Monostable multivibrator is called one-shot or single-shot circuit because it
can be used once
can be used single and not with other circuits.
always returns by itself to its single stable state
changes to quasistable for a fixed period of time upon receipt of triggering signal.

⇒ For a two- port reciprocal network, the output open circuit voltage divided by the input current is equal to
B
Z₁₂
1/y₁₂
h₁₂

⇒ The static characteristic of an adequately forward biased p-n junction is a straight line if the plot is of
log I vs log V
log I vs V
I vs log V
I vs V

⇒ All magnetic materials exhibit the phenomenon of saturation.
TRUE
FALSE

⇒ Which of the following expressions is invalid in Fortran?
IA + IB
IB * IC / ID
IA * B
- K * I + J

⇒ The number of flags available in 6800 are
6
5
7
4

⇒ The 2's complement representation of - 17 is
1110
1111
11110
10001

⇒ The requirements of carrier frequency are
precise frequency value
low frequency drift
both (a) and (b)
neither (a) nor (b)

⇒ For a series R-L-C circuit, the characteristic equation is given
critically damped
underdamped
undamped
overdamped

⇒ In a communication system, noise is most likely to affect the signal
at the receiver
at the transmitter
at the information source
in the channel

⇒ Consider the following DO statement in Fortran 77 10
2
5
zero

⇒ An astable multivibrator circuit using IC 555 timer is shown below. Assume that the circuit is oscillating stea
3 V to 5 V
3 V to 6 V
3.6 V to 6 V
3.6 V to 5 V

⇒ The electric energy required to raise the temperature of a given amount of water is 1000 kWh. If heat losses are 25%, the total heating energy required is __________ kWh.
1500
1250
1333
1000

⇒ An ideal rectifier should have
100% efficiency, zero ripple factor, zero harmonic factor and unity displacement factor
100% efficiency, zero tipple factor, zero harmonic factor and zero displacement factor
100% efficiency, zero ripple factor, unity harmonic factor and unity displacement factor
100% efficiency, unity ripple factor, zero harmonic factor and unity displacement factor

⇒ A two stage amplifier has an upper cutoff frequency of 2 MHz and a lower cutoff frequency of 2 MHz and a lower cut off frequency of 30 Hz. If both stages are similar, their individual upper and lower cut off frequencies respectively are
4 MHz and 60 MHz
3 MHz and 20 Hz
3 MHz and 60 Hz
4 MHz and 20 Hz

⇒ Which of following antenna not produces circular polarisation?
Helical
Parabolic
Disc
Yagi

⇒ CMRR of a difference amplifier is equal to
(A_v')/(A_com)
A_v/A_com
A_com/A_v'
(A_v)/(A_com)²

⇒ The discussing sharing of a communication satellite by many geographically dispersed Earth station, DAMA means
Demand-Assigned Multiple Access
Decibel Attenuated Microwave Access
Digital Analog Master Antenna
Dynamically-Assigned Multiple Access

⇒ Holes and electrons move in opposite directions.
TRUE
FALSE

⇒ In the circuit shown in the figure, the approximate voltage at the transist
base and emitter respectively are -8 V and -7.3 V
base and collector respectively are -8 V and -5 V
Collector and emitter respectively are -5 V and -7.3
base, emitter and collector respectively are -8 V, 7.3 V and -5 V

⇒ Which one of the following cannot be used to remove the unwanted sideband in SSB?
Balanced modulator
Phase shift method
Filter system
Third method

⇒ In the above case the modulation index will be
9.6
28.8
57.6
100