Question is ⇒ Let the initial contents of <code>ACC and CY</code> in 8085 be <code><ol style="list-style-type: decimal; padding-bottom:10px;"><li style="padding-top:10px;">CY = 1</li><li style="padding-top:10px;">ACC = 10000001</li></ol></code> After the instruction <code>RAL</code> is executed twice the contents of <code>CY and ACC</code> respectively will be, Options are ⇒ (A) 1 and 00000011, (B) 0 and 00000111, (C) 1 and 00000111, (D) 0 and 00000011, (E) , Leave your comments or Download question paper.

Question is ⇒ Let the initial contents of <code>ACC and CY</code> in 8085 be <code><ol style="list-style-type: decimal; padding-bottom:10px;"><li style="padding-top:10px;">CY = 1</li><li style="padding-top:10px;">ACC = 10000001</li></ol></code> After the instruction <code>RAL</code> is executed twice the contents of <code>CY and ACC</code> respectively will be, Options are ⇒ (A) 1 and 00000011, (B) 0 and 00000111, (C) 1 and 00000111, (D) 0 and 00000011, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	Let the initial contents of `ACC and CY` in 8085 be `CY = 1 ACC = 10000001` After the instruction `RAL` is executed twice the contents of `CY and ACC` respectively will be
A.	1 and 00000011 [Wrong Answer]
B.	0 and 00000111 [Correct Answer]
C.	1 and 00000111 [Wrong Answer]
D.	0 and 00000011 [Wrong Answer]
View Answer 1 -1 Explanation:- Answer : B Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

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