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Q1. | Inductance affects the direct current flow |

A. | Only at the time of turning off [Wrong Answer] |

B. | Only at the time of turning on [Wrong Answer] |

C. | At the time of turning on and off [Correct Answer] |

D. | At all the time of operation [Wrong Answer] |

View Answer
Explanation:-
Answer : CDiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ Selectivities of different resonance circuits are compared in terms of their

Impedances

Reactances

Frequencies

Band widths

⇒ A resonance curve for a series circuit is a plot of frequency versus

Current

Voltage

Impedance

Reactance

⇒ For the same peak value, which of the following wave has the least mean value ?

Half wave rectified sine wave

Triangular wave

Sine wave

Square wave

⇒ Skin effect occurs when a conductor carries current at____ frequencies.

Very low

Low

Medium

High

⇒ In A.C. circuit the power curve is a sine wave having

Double the frequency of voltage

Same frequency as that of voltage

Half the frequency of the voltage

None of these

⇒ For the same peak value of voltage which wave form will have the least r.m.s. value ?

Sine wave

Square wave

Triangular wave

Full wave rectified sine wave

⇒ A sine wave of voltage varies from zero to maximum of 200 V. How much is the voltage at the instant of 30° of the cycle ?

50V

82.8V

100V

173.2 V

⇒ How much r.m.s. current does a 300 W. 200V bulb take from the 200 V, 50 Hz power line ?

0.5A

1.5 A

2A

3A

⇒ Higher the Q of a series circuit

Broader its resonance curve

Narrower its pass band

Greater its band width

Sharper its resonace

⇒ The period of a wave is

The same as frequency

Time required to complete one cycle

Expressed in amperes

None of the above

⇒ The unit of frequency of an A.C. signal is

Cycle

Cycle-sec

Hertz

Hertz/sec

⇒ A parallel resonant circuit can be used

As a high impedance

To reject a small band of frequencies

Both (A) and (B)

To amplify certain frequencies

⇒ A heater is rated as 230 V, 10 KW, AC. The value 230 V refers t

Average voltage

r.m.s. voltage

Peak voltage

None of these

⇒ The shunt element in a band pass filter is

Capacitive

Inductive

Parallel combination of L and C

Series combination of L and C

⇒ At half power points of a resonance curve, the current is____ times the maximum current.

1/2

1/ √2

√2

2

⇒ In a parallel R-C circuit, the current always ____the applied voltage.

Lags

Leads

Remains in phase with

None of the above

⇒ The ratio of active power to apparent power is known as ____ factor.

Demand

Load

Power

Form

⇒ For a sine wave with peak value I

_{max}the r.m.s. value is

0.5 I

_{max}

0.707 I

_{max}

0.9 I

_{max}

1.414 I

_{max}

⇒ Inductance affects the direct current flow

Only at the time of turning off

Only at the time of turning on

At the time of turning on and off

At all the time of operation

⇒ The power taken by a 3-Φ load is given by the expression

√3 V

_{L}I

_{L}sinΦ

√3 V

_{L}I

_{L}cosΦ

3 V

_{L}I

_{L}sinΦ

3 V

_{L}I

_{L}cosΦ

⇒ Poor power factor results in all of the following EXCEPT.

Overloading of transformers

Overloading of altemators

Reduction in power losses

Reduction in load handling capacity of electrical system

⇒ What inductance will give the same reactance as a capacitor of 2 µF when both are at 50 Hz?

5 H

10 H

15 H

20 H

⇒ The reflection co-efficient of the simplest standing wave is

+1

1

Zero

Infinity

⇒ The power factor of incandescent bulb is

0.8 lagging

0.8 leading

Unity

Zero

⇒ When an alternating current passes through an ohmic resistance the electrical power converted into heat is

Apparent power

True power

Reactive power

None of the above

⇒ The power factor of a series R-L-C circuit at its half-power points is

Unity

Lagging

Leading

Lagging or leading

⇒ In an A.C. circuit, a low value of kVAR compared with kW indicates

Low efficiency

High power factor

Unity power factor

Maximum Load current

⇒ The capacitors for power factor correction are rated in terms of

Voltage

VA

kW

kVAR

⇒ Power factor of the following circuit will be zero

Resistance

Inductance

Capacitance

Both (B) and (C)

⇒ The value of operator j2 is equal to

Zero

+1

-1

√-1