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Q1. | In TV broadcast, UHF range is |

A. | 606 - 790 MHz [Correct Answer] |

B. | 100 - 150 MHz [Wrong Answer] |

C. | 41 - 68 MHz [Wrong Answer] |

D. | 174 - 230 MHz [Wrong Answer] |

View Answer
Explanation:-
Answer : ADiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ In case of antenna the ratio of the power radiated in the desired direction to the power radiated in the opposite direction is known as

transmission efficiency

front to back ratio

loss coefficient

none of the above

⇒ An ideal voltage amplifier should have

low input impedance and high output impedance

high input impedance and low output impedance

high input impedance and high output impedance

low input impedance and low output impedance

⇒ Symbol shown in figure represen

P-channel DMOSFET

N-channel DMOSFET

UJT with P-type base

UJT with N-type base

⇒ The dual of the function A(BC + BC + BC) is

A + (B + C) (B + C) (B + C)

A (BC + BC + BC)

C(BA + CA + CA)

ABC + ABC + ABC

⇒ What is meant by "continuous collector current" in BJT?

Maximum collector current

Current at Quiescent condition

Leakage current

Junction Capacitance charging and discharging current

⇒

**Assertion (A):** Divide-64 counter is a Mod-64 counter and divides the input frequency by 64

**Reason (R):** A Mod 64 counter can be obtained by cascading Mod 16 and Mod 4 counters.

Both A and R are correct and R is correct explanation of A

Both A and R are correct but R is not correct explanation of A

A is true, R is false

A is false, R is true

⇒ The chip 8254 is a 40 pin programmable interval timer. The number of its independent 16 bit counters is

2

3

4

5

⇒

Match the following:

List I (Application of circuit) | List II (Circuit Name) | ||
---|---|---|---|

A. | Divider | 1. | Astable multivibrator |

B. | Clips input voltage at two predetermined levels | 2. | Schmitt trigger |

C. | Square wave generator | 3. | Bistable multivibrator |

D. | Narrow current pulse generator |

A-4, B-2, C-1, D-3

A-3, B-2, C-1, D-4

A-4, B-1, C-2, D-3

A-3, B-1, C-2, D-4

⇒ The circuit of figure is used to measure the value R

_{x}. Ammeter resistance R

_{a}= 0.1 Ω voltmeter resistance R

_{v}= 5000 Ω. It R

_{x1}and R

_{x2}, are the measured values of R

_{x}with switch in position 1 and 2, the mean of R

_{x1}, and R

_{x2},

9.98 Ω

10 Ω

10.04 Ω

10.1 Ω

⇒ The current through a 10 Ω resistance in a dc circuit having two emf sources is 3A. If this resistance is changed to 20 Ω, the new value of current will be

less than 3 A

equal or less than 3 A

equal to or less or more than 3 A

1.5 A

⇒ Harmonic distortion in CB amplifier may be least when the load resistance is

negligible

very low

very high

infinite

⇒ The phase difference between them is __________ degrees.

15

50

60

105

⇒ In a low power factor wattmeter, the resistance of pressure coil is more than in ordinary wattmeter.

TRUE

FALSE

⇒ In a dual converter operated in circulating current mode, the circulating current flows

when load current is zero

when load current is non-zero

even when load current is zero

none of the above

⇒

Match the following:

List I (Symbol in java) | List II (Meaning) | ||
---|---|---|---|

A. | & | 1. | Logical AND |

B. | ˆ | 2. | AND |

C. | | | | 3. | XOR |

D. | & & | 4. | Logical OR |

A-1, B-2, C-3, D-4

A-2, B-3, C-1, D-4

A-4, B-2, C-3, D-1

A-2, B-3, C-4, D-1

⇒ A XOR gate has inputs A and B and output Y. Then the output equation is

Y = AB

Y = AB + A B

Y = A B + A B

Y = A B + A B

⇒ Consider the following statements regarding the class-B power amplifiers (Complementary symmetry type):

- The efficiency of the amplifier is higher than that of class-A amplifier
- The power output is low
- Crossover distortion is present
- The standby power dissipation is absent.

1, 2 and 3

1, 2 and 4

1, 3 and 4

2, 3 and 4

⇒ In a C expression using assignment operators, relational operators and arithmetic operators, the hierarchy of operations (in the absence of parenthesis) is

assignment, relational, arithmetic

relational, assignment, arithmetic

arithmetic, assignment, relational

arithmetic, relational, assignment

⇒ In which mode of BJT operation are both junctions forward biased?

Active

Saturation

Cut off

Reverse active

⇒ A moving iron instrument gives correct reading when used at

low frequencies

high frequencies

only one frequency

all frequencies upto a certain value

⇒ If X(

*z*) = (1 - a

*z*

^{-1})

^{-1}and |a| < |

*z*|, the initial value

*x*

_{0}= 0

TRUE

FALSE

⇒

**Assertion (A):** A transducer needs an output measuring or display device for measuring a non electrical quantity.

**Reason (R):** In some transducers the output voltage is too small and needs amplification before it can be measured.

Both A and R are true and R is correct explanation of A

Both A and R are true but R is not correct explanation of A

A is true R is false

A is false R is true

⇒ A communication channel with AWGN operating at a signal to noise ratio SNR >> 1 and bandwidth B has capacity C

_{1}. If the SNR is doubled keeping B constant, the resulting capacity C

_{2}is given by

C

_{2}≈ 2C

_{1}

C

_{2}≈ C

_{1}+ B

C

_{2}≈ C

_{1}+ 2B

C

_{2}≈ C

_{1}+ 0.3B

⇒ The characteristic impedance of a cable is about

300 Ω

50 Ω

5 Ω

2 Ω

⇒ In the given figure,

(A + B)C + DE

AB + C(D + E)

(A + B)C + D + E

none of the above

⇒ In a thermocouple two metal junctions between metals

*M*

_{1}and

*M*

_{2}are kept at temperature

*T*

_{1}and

*T*

_{2}. The thermocouple emf is produced because

M

_{1}, M

_{2}are similar and T

_{1}, T

_{2}are equal

M

_{1}, M

_{2}are similar but T

_{1}, T

_{2}are unequal

M

_{1}, M

_{2}are dissimilar but T

_{1}, T

_{2}are equal

M

_{1}, M

_{2}are dissimilar but T

_{1}, T

_{2}are unequal

⇒ The distance at which a sky wave is received back on earth decreases with angle of incidence for all angles of incidence.

TRUE

FALSE

⇒ In figure, I

_{D}= 4 mA. Then V

_{S20 V16 V6 V0.6 V}

⇒ For a message signal

*m*(

*t*) = cos (2p

*f*) and the carrier frequency

_{m}t*f*, which of the following represents a single side band (SSB) signal?

_{c}cos (2p

*f*) cos (2p

_{m}t*f*)

_{c}tcos (2p

*f*)

_{c}tcos [2p(

*f*+

_{c}*f*) t]

_{m}[1 + cos (2p

*f*) cos (2p

_{m}t*f*)]

_{c}t⇒ For a stable system

both phase and gain margin are negative

both phase and gain margin are positive

phase margin is positive but gain margin is negative

gain margin is positive but phase margin is negative