Question is ⇒ In the absence of noise, if C is channel capacity in bits/s, δf is channel bandwidth in Hz and N is number of coding levels. Then, Options are ⇒ (A) C = log2 N, (B) C = (δf) log2 N, (C) C = 2 (δf) log2 N, (D) C = 0.5 (δf) log2 N, (E) , Leave your comments or Download question paper.

Question is ⇒ In the absence of noise, if C is channel capacity in bits/s, δf is channel bandwidth in Hz and N is number of coding levels. Then, Options are ⇒ (A) C = log2 N, (B) C = (δf) log2 N, (C) C = 2 (δf) log2 N, (D) C = 0.5 (δf) log2 N, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	In the absence of noise, if C is channel capacity in bits/s, δf is channel bandwidth in Hz and N is number of coding levels. Then
A.	C = log₂ N [Wrong Answer]
B.	C = (δf) log₂ N [Wrong Answer]
C.	C = 2 (δf) log₂ N [Correct Answer]
D.	C = 0.5 (δf) log₂ N [Wrong Answer]
View Answer 1 -1 Explanation:- Answer : C Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

Previous question Next question

Also Read Similar Questions Below :

⇒ Which of the following is a valid real constant?
1281
1281
KM
11821

⇒ The instruction MVI A, 20 in 8085 means
contents of memory location 20 are brought into the accumulator
the value 20 is brought into accumulator
either (a) or (b)
neither (a) nor (b)

⇒ Consider the following part of a C program float a
2 and 9
2.0 and 9.0
2.0 and 2.0
9.0 and 2.0

⇒ AC hum is picked up from power cables
TRUE
FALSE

⇒

Assertion (A): A capacitor with imperfect dielectric can be represented by a capacitance in parallel with resistance.

Reason (R): For imperfect dielectrics, dielectric constant has real and imaginary parts.

Both A and R are true and R is correct explanation of A
Both A and R are true but R is not correct explanation of A
A is true but R is false
A is false but R is true

⇒ Figure shows a pole zero plot of I(s). The likely current response in time domai
i (t) = e^-1 - e^-3t
i (t) = e^-1 - 2e^-2t
i (t) = e^-1 - e^-2t
i (t) = e^-1 - e^-4t

⇒ The oscillator shown in figure
Clapp oscillator
R-C Phase shift oscillator
Hartley oscillator
Colpitt's oscillator

⇒ Which of the following plot can be used to show the input volt-ampere characteristics of a common-emitter configuration?
V_BE versus i_B for constant values of V_CE
V_CE versus i_C for constant values of I_B
V_CE versus i_C for constant values of I_E
None of the above

⇒ Choose the correct statement/statements :
In case of an antenna, the antenna resistance and loss resistance are not two different quantities.
The loss resistance includes loss by eddy currents, improper earth connections, insulation leakages, etc., but not I²R losses.
Radiation resistance varies directly as square-root of frequency
None

⇒ In the given figure forward current wave has a magnitud
0.45 A
0.3 A
0.2 A
0.1 A

⇒ Which one of the following is not necessarily an advantage of the phase cancellation method of obtaining SSB over the filter method?
It is possible to generate SSB at any frequency
SSB with lower audio frequencies present can be generated
Switching from one sideband to other is simpler
There are more balanced modulators; therefore the carrier is suppressed better

⇒ Simplify : A + B + A B + (A + B)AB + C(B + AB)
B + A
C
C
1

⇒ In a FM waveform, the side bands are spaced at intervals equal to
four times the modulating frequency
twice the modulating frequency
half the modulating frequency
modulating frequency

⇒ In a two phase servomotor the voltages applied to the two stator windings
are equal in magnitude and are in phase
are unequal in magnitude but are in phase
are equal in magnitude but have a phase difference of 90°
are unequal in magnitude and have a phase difference of 90°

⇒ The problem of logic race occurs in
SOP functions
POS functions
Hybrid function
SOP and POS functions

⇒ One of the advantages of base modulation over collector modulation of a transistor class C amplifier is
improved efficiency
better linearity
high power output per transistor
the lower modulating power requirement

⇒ In figure, the current supplied by battery immediately after switching on the circui
0.0416666666666667
0.166666666666667
0.416666666666667
0

⇒ Consider the following

The first letter of a Java variable is lower case.
Each successive word in Java variable begins with a capital letter.
All other letters are lower case.
A Java variable can have a digit as first character.

Which of the above are correct?
All
1, 2, 3 only
1, 2, 4 only
2, 3, 4 only

⇒ Y = A + A B is the same as
Y = AB
Y = A + B
Y = A + B
Y = A + B

⇒ In a proportional plus integral control action
proportional gain K_p is adjustable but integral time T_i is constant
proportional gain K_p is adjustable but integral time T_i is adjustable
both proportional gain K_p and integral time T_i are adjustable
both proportional gain K_p and integral time T_i are constant

⇒ Directivity of antenna is defined as
maximum directive gain
average directive gain
∞
0

⇒ Java's syntax is based on
C
C + +
Fortran 77
Pascal

⇒ The main purpose of using transformer coupling in a class A amplifier is to make it more
efficient
less costly
less bulky
distortion free

⇒ If R(t) is autocorrelation of a waveform v(t) and R(0) is autocorrelation for t = 0, then
R(0) > R(t)
R(0) ≥ R(t)
R(0) < R(t)
R(0) ≤ R(t)

⇒ In figure, the curre
is 2 A from A to B
is 2 A from B to A
depends on the value of R
none of the above

⇒ What is the gray code word for EX-OR the binary number 101011?
101011
110101
111110
11111

⇒ Wagner earthing device is used to eliminate error due to
electromagnetic coupling
electrostatic coupling
both electrostatic and electromagnetic coupling
either (a) or (b)

⇒ The geostationary communication satellite APPLE is parked in the equatorial orbit at
102° E longitude over Sumatra
90° E longitude over Bangladesh
74° E longitude over India
67° E longitude over Pakistan

⇒ An 8085 executes the following instructionsPC = 2715 H HL = 30A0 H
PC = 30A0H HL = 2715H
PC = 6104 H HL = 6140 H
PC = 6140H HL = 2715H

⇒ The inputs to a 3 bit binary adder are 111₂ and 110₂. The output will be
101
1101
1111
1110