Question is ⇒ In calculating input impedance, the load impedance is considered to be connected at the output., Options are ⇒ (A) TRUE, (B) FALSE, (C) , (D) , (E) , Leave your comments or Download question paper.

Question is ⇒ In calculating input impedance, the load impedance is considered to be connected at the output., Options are ⇒ (A) TRUE, (B) FALSE, (C) , (D) , (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	In calculating input impedance, the load impedance is considered to be connected at the output.
A.	TRUE [Correct Answer]
B.	FALSE [Wrong Answer]
View Answer 1 -1 Explanation:- Answer : A Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

Previous question Next question

Also Read Similar Questions Below :

⇒ If the poles lie in second quadrant, damping ratio is
1
less than 1
zero
more than 1

⇒ A fascimile reproduction has a specification of 200 lines per frame, progressive scanning and 5 frames per second. The time to scan one line is
5 ms
2.5 ms
1 ms
0.1 ms

⇒ Which of the following terms are applicable to troposcatter propagation?
Faradays rotation
SIOs
Fading
Atmospheric storms

⇒ The noise figure of FET circuit is
independent of the quiescent point
dependent on the quiescent point only
dependent on the triggering mechanism
independent of all above

⇒ To measure moisture in wood, the most suitable method is
electric conduction
electrical-capacitive
absorption of radiation
equilibrium-moisture Vs humidity

⇒ In the CE equivalent circuit of figure, the voltage gai
200
40
5
1000

⇒ In a series RLC circuit, the current at resonance is I₀ the total energy stored in the circuit at resonance is
LI₀²
2 LI₀²
2 LI₀²
0.5 LI²

⇒ A step voltages is applied to RLC series circuit having R = 2 Ω, L = 1 H and C = 1 F. The transient current response will be
over damped
critically damped
under damped
any of the above depending the magnitude of voltage

⇒ For representing two sinusoidal voltages on a phasor diagram
Both voltages must be of the same frequency
Both voltages must be sinusoidal but may be of different frequencies
One of the voltages must be of 50 Hz
The frequency of one must be integral of that of other

⇒ Choose the correct option, if b (branch), n (nodes), l (links)
b = n + l - 1
no. of twig = n - 1
b = n - l + 1
b, a

⇒

Assertion (A): A BJT can be used as a switch.

Reason (R): In forward active mode emitter base junction is forward biased and base collector junction is reverse biased.

Both A and R are true and R is correct explanation of A
Both A and R are true but R is not a correct explanation of A
A is true but R is false
A is false but R is true

⇒ Consider the following

A signal f(t) and its Hilbert transform f_h(t) have the same energy density spectrum
A signal f(t) and its Hilbert transform, f_h(t) have the same auto correlation function
A signal f(t) and its Hilbert transform are mutually orthogonal

Which of the above are true?
1, 2 and 3
1 and 2 only
1 only
2 and 3 only

⇒ The Hilbert transform of cos ω₁t + sin ω₂t is
sin ω₁t + cos ω₂t
sin ω₁t - cos ω₂t
cos ω₁t - cos ω₂t
- sin ω₁t + cos ω₂t

⇒ The line of sight communication requires that transmit and receive antennas to face each other. If the transmit antenna is vertically polarized, for the best reception the receive antenna should be
horizontally polarized
vertically polarized
at 45° with respect to horizontal polarization
at 45° with respect to vertical polarization

⇒ For the circuit shown in the figure, the capacitor C is initially uncharged. At t = 0, the switch S is closed. The voltage V_c across the capacitor at t = 1 millisecond is (In the figure shown above, the op-amp is supplied with ± 15 V and the ground has been shown by the sym
0 V
6.3 V
9.45 volts
10 volts

⇒

Assertion (A): FET is a unipolar device.

Reason (R): BJT is bipolar device.

Both A and R are true and R is correct explanation of A
Both A and R are true but R is not a correct explanation of A
A is true but R is false
A is false but R is true

⇒ The fact that domains exhibits spontaneous magnetisation is
first hypothesis is of Curie
second hypothesis is of Weiss
Curie-Weiss law
Boltzmann's statistics

⇒ In 8085
RST 6.5 and RST 5.5 are high level sensitive interrupts
RST 6.5 and RST 5.5 are low level sensitive interrupts
RST 5.5 is low level sensitive interrupt but RST 5.5 is high level-sensitive interrupt
RST 5.5 is low level sensitive interrupt but RST 6.5 is high level sensitive interrupt

⇒ A coil has a resistance of 2 Ω and inductance of 0.1 mH. The applied voltages is suddenly increased from 10 V to 20 V. After steady state condition have reached, the current is
0.0833333333333333
more than 2 A but less than 4 A
0.166666666666667
more than 4 A

⇒ The dimension of flux density is
MT^-1Q^-1
MT^-2
MT¹Q¹
MT^-1Q^-2

⇒ Calculate the resistivity of n-type semiconductor from the following data, Density of holes = 5 x 10¹² cm^-3. Density of electrons = 8 x 10¹³ cm^-3, mobility of conduction electron = 2.3 x 10⁴ cm²/ V-sec and mobility of holes = 100 cm²/V-sec.
0.43 Ω-m
0.34 Ω-m
0.42 Ω-m
0.24 Ω-m

⇒ Measurement of Hall coefficient enables the determination of
mobility of charge carriers
type of the conductivity and concentration of charge carriers
temperature coefficient and thermal conductivity
fermi level and forbidden energy gap

⇒ For real and odd signals, the Fourier series coefficient a_n is
purely imaginary
purely real and even
purely imaginary and odd
purely real and odd

⇒ A 100 + j 100 Ω load is to be matched to a line with Z₀ = 300 Ω to give SWR = 1. The reactance of stub is
j 200 Ω
-j 200 Ω
j 100 Ω
-j 100 Ω

⇒ In communication receivers the fidelity is provided by
audio stage
detector range
mixer stage
all of the above

⇒ When the gate terminal of MOSFET is positive, it is said to operate in
depletion mode
conduction mode
enhancement mode
none of the above

⇒ In the context of error detection in satellite transmission, ARQ stands for
Automatic Repeat Request
Automatic Relay Request
Accelerated Recovery Request
Automatic Radiation Quenching

⇒ An end fire array consisting of several half-wave lengths of directive gain 40, then array length will be
10 λ
100 λ
20 λ
5 λ

⇒ A complementary symmetry amplifier has
1 P-N-P and 1 N-P-N transistor
2 P-N-P transistor
2 N-P-N transistor
2 P-channel FETs

⇒ The modulation index of a narrowband FM signal is
nearly equal to 0.3
much less than unity
nearly 0.5
much more than unity