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In an ac network the sum of currents entering a node is 10 ∠45°. The sum of currents leaving the node is | |
A. | 19.32 ∠45° [Correct Answer] |
B. | 15 ∠45° [Wrong Answer] |
C. | 20 ∠45° [Wrong Answer] |
D. | zero [Wrong Answer] |
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