Question is ⇒ In a series R-L circuit when excited by a 1 volt battery the current is 1 - e-t. If it is excited by a source 2 sin t, the current will be, Options are ⇒ (A) 2 sin (t - 45°) + e-t, (B) 2 sin (t + 45°) + e-t, (C) sin (t - 45°) + e-t, (D) sin (t + 45°) + e-t, (E) , Leave your comments or Download question paper.

Question is ⇒ In a series R-L circuit when excited by a 1 volt battery the current is 1 - e-t. If it is excited by a source 2 sin t, the current will be, Options are ⇒ (A) 2 sin (t - 45°) + e-t, (B) 2 sin (t + 45°) + e-t, (C) sin (t - 45°) + e-t, (D) sin (t + 45°) + e-t, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	In a series R-L circuit when excited by a 1 volt battery the current is 1 - e^-t. If it is excited by a source 2 sin t, the current will be
A.	2 sin (t - 45°) + e^-t [Correct Answer]
B.	2 sin (t + 45°) + e^-t [Wrong Answer]
C.	sin (t - 45°) + e^-t [Wrong Answer]
D.	sin (t + 45°) + e^-t [Wrong Answer]
View Answer 1 -1 Explanation:- Answer : A Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

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