Question is ⇒ In a semiconductor material. The hole concentration is found to be 2 x 2.5 x 1015 cm-3. If mobility of carriers is 0.13 m2/ v-s. Then find the current density if electric field intensity is 3.62 x 10-19, Options are ⇒ (A) 7.6237 x 10-4 A/cm2, (B) 7.6237 x 10-5 A/cm2, (C) 7.6237 x 10-3 A/cm2, (D) none of these, (E) , Leave your comments or Download question paper.

Question is ⇒ In a semiconductor material. The hole concentration is found to be 2 x 2.5 x 1015 cm-3. If mobility of carriers is 0.13 m2/ v-s. Then find the current density if electric field intensity is 3.62 x 10-19, Options are ⇒ (A) 7.6237 x 10-4 A/cm2, (B) 7.6237 x 10-5 A/cm2, (C) 7.6237 x 10-3 A/cm2, (D) none of these, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	In a semiconductor material. The hole concentration is found to be 2 x 2.5 x 10¹⁵ cm^-3. If mobility of carriers is 0.13 m²/ v-s. Then find the current density if electric field intensity is 3.62 x 10^-19
A.	7.6237 x 10^-4 A/cm² [Correct Answer]
B.	7.6237 x 10^-5 A/cm² [Wrong Answer]
C.	7.6237 x 10^-3 A/cm² [Wrong Answer]
D.	none of these [Wrong Answer]
View Answer 3 -1 Explanation:- Answer : A Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

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