Question is ⇒ Frequency shifting keying is basically a method involving, Options are ⇒ (A) amplitude modulation, (B) frequency modulation, (C) phase modulation, (D) none of the above, (E) , Leave your comments or Download question paper.

Question is ⇒ Frequency shifting keying is basically a method involving, Options are ⇒ (A) amplitude modulation, (B) frequency modulation, (C) phase modulation, (D) none of the above, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	Frequency shifting keying is basically a method involving
A.	amplitude modulation [Wrong Answer]
B.	frequency modulation [Correct Answer]
C.	phase modulation [Wrong Answer]
D.	none of the above [Wrong Answer]
View Answer 1 -1 Explanation:- Answer : B Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

Previous question Next question

Also Read Similar Questions Below :

⇒ Fermi level is the amount of energy in which
a hole can have at room temperature
an electron can have at room temperature
must be given to an electron move to conduction band
none of the above

⇒ A parallel plate capacitor with air as dielectric has a capacitance C. If the dielectric has a dielectric constant ∈_r and the remaining dimensions are the same, the capacitance will be
C/∈_r
∈_rC
∈²_rC
∈³_rC

⇒ Eddy current loss is
proportional to frequency
independent of frequency
proportional to (frequency)²
proportional to (frequency)³

⇒ The trigonometric Fourier series for the waveform f(t) shown below con
only cosine terms and zero value for the dc component
only cosine terms and a positive value for the dc component
only cosine terms and a negative value for the dc component
only sine terms and a negative for the dc component

⇒ The log magnitude plot of the given figure is
type 0 system
type 1 system
type 2 system
either type 0 or type 1 system

⇒ A wave E_m cos (bx - ωt) is a backward wave.
TRUE
FALSE

⇒

Assertion (A): Peak to peak value of a sinusoidal wave is 2.828 times the rms value.

Reason (R): Peak factor of a sinusoidal wave is 1.414.

Both A and R are true and R is correct explanation of A
Both A and R are true and R is not the correct explanation of A
A is true but R is false
A is false but R is true

⇒

Match the following:

	List I		List II
A.	T (Reflection coefficient) = 0	1.	(Z_L - Z_o)/(Z_L + Z_o)
B.	T = - 1	2.	Z_L = Z_o
C.	T = + 1	3.	Z_L = 0
D.	- 1 < T < + 1	4.	Z_L = ∞

A-2, B-3, C-4, D-1
A-2, B-4, C-1, D-3
A-1, B-2, C-3, D-4
A-3, B-2, C-4, D-1

⇒ A 256 x 4 EPROM has
8 address pins and 4 data pins
8 address pins and 8 data pins
4 address pins and 8 data pins
4 address pins and 4 data pins

⇒ Which of the following is the point of reference JFET?
Drain
Gate
Source
None of the above

⇒ For a sinusoidal input, the circuit shown in the figure will act
Pulse generator
Full wave rectifier
Ramp generator
Voltage Doubler

⇒ Wagner earthing device eliminates
all stray capacitance in the circuit
stray capacitances between components
stray capacitance between detector terminal and ground
mutual coupling between components

⇒ The output of a Mealy system is 1 if there has been a pattern of 11000, otherwise 0. The minimum state for this system is :
4
5
6
7

⇒ A loss less line of characteristic impedance Z₀ is terminated in pure reactance of -jZ₀ value. VSWR is
10
2
1
infinity

⇒ In the basic series inverter circuit, the source current has
low harmonic content
high harmonic content
low or high harmonic content depending on firing angle
zero harmonic content

⇒ In drawing phasor diagram
rms values are used
peak values are used
either rms or peak values are used
either rms or peak or averages values are used

⇒ The factor which will have least effect on the voltage at the load end of a two-wire supply circuit is
length of the circuit
whether supply frequency is 25 Hz or 50 Hz
amount of load on the circuit
cross-section of the circuit wires

⇒ An electron (charge -e) is rotating in a circular orbit of radius R, around a proton with charge +e at a constant angular velocity ω. The orbital magnetic dipole moment is
0.5 eω R²
eω R²
2 eω R²
0.5 eω R³

⇒ In the given figure shows a root locus plot. Consider the following statements for this plot

The open loop system is a second order system
The system is overdamped for K > 1
The system is stable for all values of K

Which of the above statements are corr
1, 2, 3
1, 3
2, 3
1, 2

⇒ The antenna current of an AM broad cast transmitter, modulated to a depth of 40% by an audio sine wave is 11 amperes. It increased to 12 ampere as a result of simultaneous modulation by another sine wave. The modulation index due to this second sine wave is :
0.4
0.757
0.643
0.8

⇒ The resonant frequency of the circuit shown in figure
1/22p Hz
1/2p Hz
1/4p Hz
1/2p Hz

⇒ Ferroelectric materials are those which
cannot be polarized
have a permanent polarization
have a_e equal to zero
have μ_p = 0

⇒ Thyristors connected in series need static and dynamic stabilizing circuits.
TRUE
FALSE

⇒

Assertion (A): A VMOS can handle much larger current than other field effect transistors.

Reason (R): In a VMOS the conducting channel is very narrow.

Both A and R are true and R is correct explanation of A
Both A and R are true but R is not a correct explanation of A
A is true but R is false
A is false but R is true

⇒ If in a broadcasting studio, a 1000 kHz carrier is modulated by an audio signal of frequency range 100-5000 kHz, the width of channel is __________ kHz.
5
4.9
995
10

⇒ In figure the dc emitter current of each transistor is a
4 mA
2 mA
3 mA
1 mA

⇒ The image frequency of a superheterodyne receiver is
independent of the frequency at which the receiver is tuned
always outside the operating range of the receiver
typical to FM receivers only
not rejected by the IF tuned circuits

⇒ End fire coupler is formed
when two equal radiators are operated in phase quadrature at a distance of λ/4 apart
when two equal radiators are operated in parallel at a distance of λ/4 apart
when two equal radiators are operated in phase quadrature at a distance of λ/2 apart
none of the above

⇒ Voltage V_L in the circuit when V_s < 0 where D is an ideal diode. (Take R₁ = R_s = R_L = 1 &o
0
1
1.5
cannot find

⇒ An RC impadence function has a pole at s = 0. The first element in the Foster form of synthesis
is R
may be R and C
is C
is R and C in parallel