Users Also Read

MCQ's Search Engine

Electrical Engineering

Mechanical Engineering

Civil Engineering

Automobile Engineering

Chemical Engineering

Computer Engineering

Electronics Engineering

Medical Science Engg

Q1. | For the circuit of figure the input and output Miller resistances |

A. | 5 kΩ each [Wrong Answer] |

B. | 1 ohm and 5 kΩ respectively [Correct Answer] |

C. | 5 kΩ and 1 ohm respectively [Wrong Answer] |

D. | 1 ohm each [Wrong Answer] |

View Answer
Explanation:-
Answer : BDiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ In the circuit of figure the current through 3 Ω resistance at

*t*= &infin

0.166666666666667

2.5 A

3.1 A

0

⇒ Consider the differential amplifier shown in figure. (Assume β is very hi

5 V

10 V

15 V

30 V

⇒ The Truth Table shown is f

CMO

counter

flip-flop

half adder

⇒ Television signals are propagated as ground waves.

TRUE

FALSE

⇒ At millimeter wavelength the favoured mode in circular wave guide is

TE

_{01}

TE

_{11}

TE

_{20}

TE

_{21 }

⇒ A 1000 kHz carrier is simultaneously modulated by 300 Hz and 2 kHz audio sine wave. Which of the following frequencies will not be present in the output?

998 kHz

999.7 kHz

1000.3 kHz

700 kHz

⇒

Match the following:

List I | List II | ||
---|---|---|---|

A. | Wein bridge oscillator | 1. | Low output impedance |

B. | Voltage shunt feedback amplifier | 2. | RF frequency range |

C. | Crystal oscillator | 3. | Audio frequency range |

D. | Current shunt feedback amplifier | 4. | High input impedance |

5. | High output impedance |

A-3, B-1, C-2, D-5

A-3, B-5, C-1, D-2

A-4, B-3, C-1, D-2

A-5, B-1, C-2, D-1

⇒ Average latency time of magnetic tape memory is of the order of

1 μ sec

1 msec

1 sec

1 minute

⇒ A current of 3.25 A is flowing through a resistance of 34.98 Ω. The voltage drop across resistance to the appropriate number of significant figures is

113.685 V

113.68 V

113.6 V

114 V

⇒ A linear time-invariant, causal continuous time system has a rational transfer function with simple poles at

*s*= - 2 and

*s*= - 4, and one simple zero at

*s*= - 1. A unit step

*u*(

*t*) is applied at the input of the system. At steady state, the output has constant value of 1. The impulse response of this system is

[exp (- 2

*t*) + exp (-4

*t*)]

*u*(

*t*)

[-4 exp (- 2

*t*) + 12 exp (-4

*t*) - exp (-

*t*)]

*u*(

*t*)

[-4 exp (- 2

*t*) + 12 exp (-4

*t*)]

*u*(

*t*)

[-0.5 exp (- 2

*t*) + 1.5 exp (-4

*t*)]

*u*(

*t*)

⇒ In the circuit shown in figure, maximum power will be transferred

Z

_{L}= 13 -

*j*9

Z

_{L}= 13 +

*j*9

Z

_{L}= 9 -

*j*13

Z

_{L}= 9 +

*j*13

⇒ Which one of the following statements is not a property of RL driving point impedance?

The first critical frequency at the origin is a zero

The last critical frequency is a pole

The impedance at S = ∞ always less than the impedance at S = zero

The slope of the impedance curve is positive at all points

⇒

**Assertion (A):** A *p-n* junction is used as rectifier.

**Reason (R):** A *p-n* junction has low resistance in forward direction and high resistance in reverse direction.

Both A and R are true and R is correct explanation of A

Both A and R are true but R is not a correct explanation of A

A is true but R is false

A is false but R is true

⇒ Two current sources each of rms value 10 A have frequencies 40 Hz and 50 Hz respectively. They are connected in series, the expression for resultant wave is

*i*= 10 sin 40

*t*+ 10 sin 50

*t*

*i*= 14.14 sin 40

*t*+ 14.14 sin 50

*t*

*i*= 14.14 sin 80 p

*t*+ 14.14 sin 100 p

*t*

*i*= 20 sin 80 p

*t*+ 20 sin 100 p

*t*

⇒ Which one of the following is a regulated power supply?

IC 555

IC 844

IC 3080

IC 723

⇒ A (75 -

*j*40) W load is connected to a co-axial line of

*z*

_{0}= 75ω at 6 MHz. The load matching on the line can be accomplished by connecting

a short circuit stub at the load

an inductance at the load

a short circuit stub at a specific distance from the load

a capacitance at a specific distance from the load

⇒ For a plane good conductor, skin depth varies

directly as square root of permeability

directly as square root of frequency

inversely as permittivity

inversely as square root of conductivity

⇒ The disadvantage of FM over AM is that

high output power is needed

high modulating power is needed

noise is very high for high frequency

large bandwidth is required

⇒ Material which lack permanent magnetic dipoles are known as

paramagnetic

diamagnetic

ferromagnetic

ferrimagnetic

⇒ The forbidden band in semiconductors is of the order of

6 eV

1 eV

10 eV

0.01 eV

⇒ The current wave in figure is passed through 3 H inductor. The voltage across inductance during the period 2 <

*t*< 3 second

12 V

- 12 V

6 V

- 6 V

⇒ In a Hurwitz polynomial

all coefficients are non-negative

the coefficients may be positive or negative

all coefficients are negative

all coefficients are non-negative and all zeros should be either in left half plane or simple on the imaginary axis

⇒ Decimal 17 in octal system is represented by

888

111

21

27

⇒ A transistor amplifier is operating in class A mode. If a transformer is connected for impedance matching, the efficiency will

increase

decrease

not be affected

increase or decrease

⇒ The advantage of using crystal oscillator is that it

requires low d.c. supply voltage

works at high frequency

gives high output voltage

gives constant frequency of oscillations

⇒ An active network has

an e.m.f source

a current source

neither of the above

either (a) or (b)

⇒ Narrow band FM signal can be represented as

A cos (2p

*f*) - β

_{c}t*A*sin (2p

*f*) sin (2p

_{c}t*f*)

_{m}tA cos (2p

*f*) - β

_{m}t*A*sin (2p

*f*) sin (2p

_{c}t*f*)

_{m}tA cos (2p

*f*) + β

_{c}t*A*sin (2p

*f*) sin (2p

_{c}t*f*)

_{m}tA cos (2p

*f*) + β

_{m}t*A*sin (2p

*f*) sin (2p

_{m}t*f*)

_{c}t⇒ Assuming that

*k*is an integer what would the result of following expression

8

7

7.5

zero

⇒ Due to the formation of Schottky defects the density of the crystal

increases slightly

increases appreciably

decreases slightly

decreases appreciably

⇒ The number of interrupt lines in 8085 is

2

3

4

5